HELP ASAP DUE IN 1 HR

7(x+3)=-2(x-5) <br> Help pls?

olganol [36]

Answer:

x = -11/9

Step-by-step explanation:

7(x+3)=-2(x-5)

Distribute

7x+21 = -2x+10

Add 2x to each side

7x+21 +2x = -2x+10+2x

9x +21 = 10

Subtract 21 from each side

9x +21-21 = 10-21

9x = -11

Divide each side by 9

9x/9 = -11/9

x = -11/9

3 0

3 years ago

Read 2 more answers

Confused on the steps and I need help

lions [1.4K]

9514 1404 393

Answer:

3) y = -1

5) x = -14

Step-by-step explanation:

The first step is to recognize that the equation describes a vertical line in problem 3 and a horizontal line in problem 5. The perpendicular to a vertical line is a horizontal line, and vice versa.

__

3. To make the desired horizontal line go through the point (-8, -1) the y-value of the line must match that of the point:

y = -1

__

5. To make the desired vertical line go through the point (-14, 81), the x-value of the line must match that of the point:

x = -14

8 0

3 years ago

Which table shows a function that is decreasing only over the interval (–1, ∞)? A 2-column table with 6 rows. The first column i

Lemur [1.5K]

Answer:

B. f(x) ≤ 0 over the interval [0, 2]. D.f(x) > 0 over the interval (–2, 0). E.f(x) ≥ 0 over the interval [2, ).

Step-by-step explanation:

Those are the 3 answers. Just did it on edge.

8 0

3 years ago

PLEASE HELP ME!!!!!!!!!!!!!!!!!!

lilavasa [31]

Answer:

a) 4 - $vt - d = \frac{1}{2} at^{2}$

b) 1 - $2(vt - d) = at^{2}$

c) 6 - $\frac{2(vt - d)}{t^{2}} = a$

Step-by-step explanation:

It simply asks the steps to go from the original displacement formula to isolate a (the acceleration). It's just a matter of moving items around.

We start with:

$d = vt - \frac{1}{2} at^{2}$

We then move the vt part on the left side, then multiply each side by -1 (to get rid of the negative on the at side and to match answer choice #4):

$vt - d = \frac{1}{2} at^{2}$

Then we multiply each side by 2 to get rid of the 1/2, answer #1:

$2(vt - d) = at^{2}$

Finally, we divide each side by t^2 to isolate a (answer #6):

$\frac{2(vt - d)}{t^{2}} = a$

4 0

3 years ago

Customers arrivals at a checkout counter in a department store per hour have a Poisson distribution with parameter λ = 7. Calcul

IgorLugansk [536]

Answer:

(1)14.9% (2) 2.96% (3) 97.04%

Step-by-step explanation:

Formula for Poisson distribution: $P(k) = \frac{\lambda^ke^{-k}}{k!}$ where k is a number of guests coming in at a particular hour period.

(1) We can substitute k = 7 and $\lambda = 7$ into the formula:

$P(k=7) = \frac{7^7e^{-7}}{7!}$

$P(k=7) = \frac{823543*0.000911882}{5040} = 0.149 = 14.9\%$

(2)To calculate the probability of maximum 2 customers, we can add up the probability of 0, 1, and 2 customers coming in at a random hours

$P(k\leq2) = P(k=0)+P(k=1)+P(k=2)$

$P(k\leq2) = \frac{7^0e^{-7}}{0!} + \frac{7^1e^{-7}}{1!} + \frac{7^2e^{-7}}{2!}$

$P(k \leq 2) = \frac{0.000911882}{1} + \frac{7*0.000911882}{1} + \frac{49*0.000911882}{2}$

$P(k\leq2) = 0.000911882+0.006383174+0.022341108 \approx 0.0296=2.96\%$

(3) The probability of having at least 3 customers arriving at a random hour would be the probability of having more than 2 customers, which is the invert of probability of having no more than 2 customers. Therefore:

$P(k\geq 3) = P(k>2) = 1 - P(k\leq2) = 1 - 0.0296 = 0.9704 = 97.04\%$

4 0

2 years ago