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Artist 52 [7]
3 years ago
5

The no. Of adel beads to that of claire's beads was the ratio 7 :4 .When adel gave 68 beads to claire the ratio become 25 :41 .

How many beads did claire did claire have finally
Mathematics
1 answer:
Novosadov [1.4K]3 years ago
4 0

Answer:

37 beads

Step-by-step explanation:

Given that:

Adel : Claire = 7 : 4

Let Adel be = A;  &

Let Claire be = C

A: C = 7 : 4

\dfrac{A}{C} =\dfrac{7}{4}

7C = 4A

C = \dfrac{4A}{7} --- (1)

When Adel gave 68 beads to claire, we have:

C + 68 = 25:41

\dfrac{A}{C+68}= \dfrac{25}{41}

25(C + 68) = 41A

C + 68 = \dfrac{41}{25}A

C = \dfrac{41}{25}A - 68 --- (2)

Equating (1) and (2) together;

\dfrac{4 * A}{7} = \dfrac{41 *A}{25} - 68

\dfrac{4 * A}{7}-\dfrac{41 *A}{25} =  - 68

\dfrac{100A - 287 A}{175} =- 68

\dfrac{-187A}{175} = -68

- 187 A = 175 × (-68)

-187 A = - 11900

A = - 11900/ -187

A ≅ 64

From; C = \dfrac{4A}{7}

C = \dfrac{4*64}{7}

C = 36.57

C ≅ 37 beads

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