The answer is the second one; 15y^2–11y
Answer:
4!
Step-by-step explanation:
Hope this helped
Jim has 27.5 minutes left to get to the airport.
We have that
H(t)=-4.9t²<span>+50t + 2
we know that
</span><span>The initial height of the rocket, in meters is for t=0 sec
fot t=0
H(t)=</span>-4.9*0²+50*0 + 2------> H(t)=2 m
the answer is
The initial height of the rocket is 2 m