<span>x^2 + 1 = 0
x^2 = -1
x =
x = i
:
(x^3 + 2x) = 0
Factor out x
x(x^2 + 2) = 0
x = 0</span>
F(x) is what they gain, and g(x) is what they lose. Therefore, it would be (f-g)(3) or first choice
Ok let’s solve it
5(x-2)^2-20=0
first let’s foil (x-2)
5(x^2-4x+4) -20=0
now distribute the 5
5x^2 -20x +20 -20 = 0
combine like terms
5x^2-20x=0
take the gcf
5x(x-4)=0
x=0, 4
solutions are (4,0) and (2, -20) because the original vertex form a(x-h)^2+k
Answer:
184704
Step-by-step explanation:
