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3 years ago

-8x+2(3x+5) Show work I’ll mark brainless

Mathematics

1 answer:

Verizon [17]3 years ago

6 0

Answer:

- 2x + 10

Step-by-step explanation:

Given

- 8x + 2(3x + 5) ← distribute parenthesis by 2

= - 8x + 6x + 10 ← collect like terms

= - 2x + 10

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If you sleep 6 hours a day every day for a year you are sleeping of every year. If there are 365 days in a year, how

alex41 [277]

Answer:

Step-by-step explanation:

365 x 24 = 8,760

365 x 6 = 2,190

8,760 - 2,190 = 6,570

6,570 / 24 = 273 3/4

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2 years ago

The velocity v of blood that flows in a blood vessel with radius r and length ℓ at a distance r from the central axis is v(r) =

pogonyaev

$v(r)=4P\eta\ell(R^2-r^2)$

(assuming $R$ is the radius of the vessel, and that $0\le r\le R$ )

The average velocity of the blood is given by

$\displaystyle\frac1{R-0}\int_{r=0}^{r=R}v(r)\,\mathrm dr$
$=\displaystyle\frac{4P\eta\ell}R\int_{r=0}^{r=R}(R^2-r^2)\,\mathrm dr$
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3 years ago

BIG IDEAS MATH <br> help me out please hurry

arsen [322]

I will but the picture is blurry

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3 years ago

Administrators at a large public high school are interested in their students’ standardized test scores. Last year, the mean sco

ratelena [41]

Answer:

The appropriate hypotheses for performing a significance test is:

$H_0: \mu = 51$

$H_1: \mu > 51$

Step-by-step explanation:

Last year, the mean score on the state’s math test was 51. The administrators have trained the teachers in a new method of teaching math hoping to raise the scores on this standardized test this year.

At the null hypothesis, we test if the mean score this year is the same as last year, that is:

$H_0: \mu = 51$

At the alternate hypothesis, we test if the mean score improved this year from last, that is:

$H_1: \mu > 51$

The appropriate hypotheses for performing a significance test is:

$H_0: \mu = 51$

$H_1: \mu > 51$

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3 years ago

Suppose that 10% of all steel shafts produced by a certain process are nonconforming but can be reworked (rather than having to

balandron [24]

Answer:

0.9905,0.9837,0.8066

Step-by-step explanation:

Given that 10% of all steel shafts produced by a certain process are nonconforming but can be reworked (rather than having to be scrapped).

Each shaft is independent of the other and probability for non conforming is the same for each trial.

Hence X the among these that are nonconforming and can be reworked. is Bin with n =200 and p = 0.10

a) $P(X\leq 30) = 0.9905$

b) $P(X$

c) $P(15\leq x\leq 25)\\= F(25)-F(14)\\= 0.8995-0.0929\\= 0.8066$

6 0

3 years ago