Answer:
equation;
Center (-4,2)
Radius is
Step-by-step explanation:
Since the x^2 and y^2 have the same coeffiecent this will be a circle in a form of
Where (h,k) is center
r is the radius
So first we group like Terms together
Add 7 to both sides
Since the orginal form of the equation of the circle has a perfect square we need to complete the square for each problem
and
so we have
To find our center, h is -4 and k is 2
so the center is (-4,2)
The radius is
So the radius is 3 times sqr root of 3.
I hope this helps you
540/100
54/10
5,4
Step-by-step explanation:
-t = 9(t-10)
-t = 9t - 90
90 = 9t + t
90 = 10t
90 ÷ 10 = t
9 = t
Answer:
The solution of system of equation is (-2,0)
Step-by-step explanation:
Given system of equation are
Equation 1 : 2x+y=(-4)
Equation 2 : y+
x=(-1)
To plot the equation of line, we need at least two points
For Equation 1 : 2x+y=(-4)
Let x=0
2x+y=(-4)
2(0)+y=(-4)
y=(-4)
Let x=1
2x+y=(-4)
2(1)+y=(-4)
y=(-6)
Therefore,
The required points for equation is (0,-4) and (1,-6)
For Equation 2 : y+x=(-1)
Let x=0
y+x=(-1)
y+(0)=(-1)
y=(-1)
Let x=2
y+x=(-1)
y+(2)=(-1)
y=(-2)
The required points for equation is (0,-1) and (2,-2)
Now, plot the graph using this points
From the graph,
The red line is equation 1 and blue line is equation 2
Since. The point of intersection is solution of system of equations
The solution of system of equation is (-2,0)
1. Add all of the numbers together
2. Divide the answer by how many different numbers there are (so 10)
The mean to the nearest tenth is
356.8
