The sum of the measures of the angles of a triangle is 180 degrees.
An isosceles triangle has two congruent sides.
The angles opposite the congruent sides are congruent.
Just like the bottom left angle measures x, the bottom right angle also measures x.
x + x + 38 = 180
2x + 38 = 180
2x = 142
x = 71
<h3>Radius = 14cm</h3>
Step-by-step explanation:
Let O be the centre of the circle. Since P and S are the points of contact of tangents AD and DC respectively, OP ⊥ AD and OS ⊥ DC
Also, AD ⊥ DC (given), therefore, OPDS is a square.
BR = BQ = 27cm...(tangents from an external point to a circle are equal in length)
therefore, CR = CB - BR = (38 - 27)cm = 11cm
SC = CR = 11 cm...(tangents from an external point) therefore, DS = DC - SC = (25 - 11) cm = 14 cm.
therefore,
Radius of a circle = OP = DS = 14 cm...(therefore, OPDS is a square).
<h3>Hope it helps you!! </h3>
Answer:
Circumference of the can is 21.98 cm.
Step-by-step explanation:
Since, top of the cylinder can shown in the figure is in the shape of a circle
Circumference of a circle is given by the formula,
Circumference 'C' = π × Diameter
Where r = radius of the circle
Therefore, circumference of a circle with diameter 7 centimeters will be,
C = 7π
= 7 × 3.14
= 21.98 cm
Therefore, circumference of the can is 21.98 cm.
Answer:
175pi units^3
Step-by-step explanation:
A P E X- just did it
Answer:
x = 5
Step-by-step explanation:
Since both sides are given, set both sides equal to eachother.
3x + 1 = 5x - 9
Segment CM is on the left and segment MB is on the right. From now on, solve for x.
Step 1: Isolate x by itself by subtracting the lesser value
3x + 1 = 5x - 9
-3x -3x the x's on the left cross out
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1 = 2x - 9
+9 +9 having x on one side
----------------
10 = 2x
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Step 2: Divide each side by 2 to get rid of x's coefficient
10 = 2x
/2 /2
----------
5 = x
Solution: x = 5
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Solving for CB: Substitute x for both sides since x = 5
3(5) + 1 = side CM
15 + 1 = side CM
16 = side CM
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Solving for CB: Solve for the other side (segment MB)
5(5) - 9 = side MB
25 - 9 = side MB
14 = side MB
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Solving for CB: Lastly, add up the sides
16 + 14 = segment CB
30 = segment CB
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