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tester [92]
2 years ago
8

Suppose that the breaking strength of a rope (in pounds) is normally distributed, with a mean of 100 pounds and a standard devia

tion of 17. What is the probability that a certain rope will break before being subjected to 130 pounds?
Mathematics
1 answer:
EleoNora [17]2 years ago
8 0

Answer:

0.961

Step-by-step explanation:

To answer this, find the area under the standard normal curve to the left of 130 pounds:

Using the function normalcdf( on a TI calculator, we get:

normalcdf(-1000, 130, 100, 17) = 0.961

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Marysya12 [62]

Answer:

(a) P(x\le 3) = 0.75

(b) P(x\le 3) = 0.75

<em>(b) is the same as (a)</em>

(c) P(x \ge 5) = 0.10

(d) P(x = 1\ or\ 2) = 0.55

(e) P(x > 2) = 0.45

Step-by-step explanation:

Given

\begin{array}{ccccccc}{CDs} & {1} & {2} & {3} & {4} & {5} & {6\ or\ more}\ \\ {Prob} & {0.30} & {0.25} & {0.20} & {0.15} & {0.05} & {0.05}\ \ \end{array}

Solving (a): Probability of 3 or fewer CDs

Here, we consider:

\begin{array}{cccc}{CDs} & {1} & {2} & {3} \ \\ {Prob} & {0.30} & {0.25} & {0.20} \ \ \end{array}

This probability is calculated as:

P(x\le 3) = P(1) + P(2) + P(3)

This gives:

P(x\le 3) = 0.30 + 0.25 + 0.20

P(x\le 3) = 0.75

Solving (b): Probability of at most 3 CDs

Here, we consider:

\begin{array}{cccc}{CDs} & {1} & {2} & {3} \ \\ {Prob} & {0.30} & {0.25} & {0.20} \ \ \end{array}

This probability is calculated as:

P(x\le 3) = P(1) + P(2) + P(3)

This gives:

P(x\le 3) = 0.30 + 0.25 + 0.20

P(x\le 3) = 0.75

<em>(b) is the same as (a)</em>

<em />

Solving (c): Probability of 5 or more CDs

Here, we consider:

\begin{array}{ccc}{CDs} & {5} & {6\ or\ more}\ \\ {Prob} & {0.05} & {0.05}\ \ \end{array}

This probability is calculated as:

P(x \ge 5) = P(5) + P(6\ or\ more)

This gives:

P(x\ge 5) = 0.05 + 0.05

P(x \ge 5) = 0.10

Solving (d): Probability of 1 or 2 CDs

Here, we consider:

\begin{array}{ccc}{CDs} & {1} & {2} \ \\ {Prob} & {0.30} & {0.25} \ \ \end{array}

This probability is calculated as:

P(x = 1\ or\ 2) = P(1) + P(2)

This gives:

P(x = 1\ or\ 2) = 0.30 + 0.25

P(x = 1\ or\ 2) = 0.55

Solving (e): Probability of more than 2 CDs

Here, we consider:

\begin{array}{ccccc}{CDs} & {3} & {4} & {5} & {6\ or\ more}\ \\ {Prob} & {0.20} & {0.15} & {0.05} & {0.05}\ \ \end{array}

This probability is calculated as:

P(x > 2) = P(3) + P(4) + P(5) + P(6\ or\ more)

This gives:

P(x > 2) = 0.20+ 0.15 + 0.05 + 0.05

P(x > 2) = 0.45

3 0
3 years ago
Three-fourths of the sum of six times a number and twelve distribute
dimaraw [331]

Answer:

Step-by-step explanation:

Let x be the number.

6 times the number = 6*x = 6x

Sum of 6 times of a number and twelve = 6x + 12

Three-fourths of the sum of 6 times of a number and twelve = \frac{3}{4}(6x +12)

\frac{3}{4} ( 6x + 12) = \frac{3}{4}*6x + \frac{3}{4}*12\\\\

                = \frac{3}{2}*3x + 3*3\\\\=\frac{9}{2}x + 9

6 0
3 years ago
Can someone please help me with writing a flowchart proof?
Keith_Richards [23]

Answer:

∠AZ = ∠BX

The two triangles are equivalent triangles

Step-by-step explanation:

Flowchart proofs are organized with boxes and arrows. The statements given are written in the box and the reason of that statement is written just below the box. Every statement if flowchart proof complements other statement.

∠AZ = ∠BX

The two triangles are equivalent triangles.

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Answer:

2. f(-7)= -3(-7)-2

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10. h(1)= | 1-7(1) |

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11. h(-7) =|1-7(-7)|

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     =48

12. [23-h(9) =|1-7(-9)|]

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      |-62|

         23-62

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Step-by-step explanation:

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3 years ago
Covert 31 days into minutes
malfutka [58]

Answer:

MARK ME AS BRAINLIEST !!

Step-by-step explanation:

44640

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2 years ago
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