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3 years ago

Help with number 20 please

Mathematics

1 answer:

zzz [600]3 years ago

4 0

Answer:

dc rbtbtbntnfffnmfnbddnfnnc

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Identify terms, coefficients, factors, and the constant: 5(2x + 4) + 3x

KATRIN_1 [288]

Answer:

Terms:

5, 2x, 4, 3x

Coefficients:

2 in 2x, and 3 in 3x

Constants:

5 and 4

Factors:

5, 2x, and 4

Step-by-step explanation:

For terms, all of them are terms because they are all in the expression.

For coefficients, coefficients are ones that have a variable (think of it as a copilot kind of thing).

For factors, factors are terms that are multiplied together together to get a product (the answer).

For constants, these are terms that stand alone, by themselves. They are not attached to variables.

The answer is 13x + 20, too, just in case you needed that.

Have a great day and hope this helps!

5 0

3 years ago

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What’s 3x+6y=12 in the form y=mx+b

zhenek [66]

Hey there!

3x+6y=12

Divide both sides by 3 and your equation would now look like:
x+2y= 4
Move the x to the other side
2y= -x+4
Seprate the y by dividing both sides by 2
y= $\frac{1}{2}$ x+2

4 0

3 years ago

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What is the rate of return when 35 shares of Stock A, purchased for $20/share, are sold for $815? The commission on the sale is

wariber [46]

Cost price:-

$\\ \sf\longmapsto 35\times 20$

$\\ \sf\longmapsto 700$

Commision=$6
Total sold price=815+6=823$

Now

Return=823-700=123

Rate of return

$\\ \sf\longmapsto \dfrac{123}{700}\times 100$

$\\ \sf\longmapsto \dfrac{123}{7}$

$\\ \sf\longmapsto 17.5\%$

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2 years ago

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X 20) Becca has 3 times more games than Susan has. Write an algebraic

vova2212 [387]

Answer:

3*x

Step-by-step explanation:

If Becca has 3 times the amount of games as Susan then you would multiply the number of games Susan has by 3. So we can use X (or another letter) to represent the number of games Susan has. Giving us 3*x

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2 years ago

How can finding the number of solutions apply to the real world? need answer fest plz

Inessa05 [86]

Answer:

it helps sharpen ur brain up for future so as not to be cheated by others

6 0

2 years ago