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Ivanshal [37]
2 years ago
5

In ΔKLM, m = 5.9 cm, k = 7.1 cm and ∠L=72°. Find the length of l, to the nearest 10th of a centimeter.

Mathematics
1 answer:
Elena L [17]2 years ago
4 0

Answer:

7.7

Step-by-step explanation:

a ^2+b^2=c^2−2bccosA

l^2 = 5.9^2+7.1^2-2(5.9)(7.1)cos 72

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If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by
Vitek1552 [10]

Answer:

a) Average velocity at 0.1 s is 696 ft/s.

b) Average velocity at 0.01 s is 7536 ft/s.

c) Average velocity at 0.001 s is 75936 ft/s.

Step-by-step explanation:

Given : If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by y = 70t-16t^2.

To find : The average velocity for the time period beginning when t = 2 and lasting.  a. 0.1 s. , b. 0.01 s. , c. 0.001 s.

Solution :    

a) The average velocity for the time period beginning when t = 2 and lasting 0.1 s.

(\text{Average velocity})_{0.1\ s}=\frac{\text{Change in height}}{0.1}

(\text{Average velocity})_{0.1\ s}=\frac{h_{2.1}-h_2}{0.1}

(\text{Average velocity})_{0.1\ s}=\frac{(70(2.1)-16(2.1)^2)-(70(0.1)-16(0.1)^2)}{0.1}

(\text{Average velocity})_{0.1\ s}=\frac{69.6}{0.1}

(\text{Average velocity})_{0.1\ s}=696\ ft/s

b) The average velocity for the time period beginning when t = 2 and lasting 0.01 s.

(\text{Average velocity})_{0.01\ s}=\frac{\text{Change in height}}{0.01}

(\text{Average velocity})_{0.01\ s}=\frac{h_{2.01}-h_2}{0.01}

(\text{Average velocity})_{0.01\ s}=\frac{(70(2.01)-16(2.01)^2)-(70(0.01)-16(0.01)^2)}{0.01}

(\text{Average velocity})_{0.01\ s}=\frac{75.36}{0.01}

(\text{Average velocity})_{0.01\ s}=7536\ ft/s

c) The average velocity for the time period beginning when t = 2 and lasting 0.001 s.

(\text{Average velocity})_{0.001\ s}=\frac{\text{Change in height}}{0.001}  

(\text{Average velocity})_{0.001\ s}=\frac{h_{2.001}-h_2}{0.001}

(\text{Average velocity})_{0.001\ s}=\frac{(70(2.001)-16(2.001)^2)-(70(0.001)-16(0.001)^2)}{0.001}

(\text{Average velocity})_{0.001\ s}=\frac{75.936}{0.001}

(\text{Average velocity})_{0.001\ s}=75936\ ft/s

5 0
3 years ago
A counterexample to show that the conjecture is false.
Drupady [299]
(3/4) / (1/11) =
3/4 * 11/1 =
33/4 <== improper
3 0
3 years ago
ASAP<br> Can someone help me with this please
Sidana [21]

Answer:

x = 2

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Help please I really need help put 1234 when your Answering them
Arturiano [62]
1.) 168 inches

2.) 96 inches
3 0
2 years ago
A suitcase measure 24 inches long and 18 inches high, what is the diagonal length of the suitcase to the nearest tenth of a foot
Alik [6]

Answer:

The diagonal length of the suitcase is 30 inches.

Hope it helps. :)

7 0
2 years ago
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