First, some housekeeping:
cos = 12/13 is incomplete; "cos" must have an argument (input).
cos x = 12/13 is fine; here "cos" has the argument (input) x.
Given that cos x = 12/13, find sin x. To do this, we'll need to find the length of the opposite side, given that the hypo length is 13 and the adj. side length is 12.
12^2 + opp^2 = 13^2, or opp^2 = 169-144 = 25.
Then the opp side could be either 5 or -5. Let's assume that it's +5, and that angle x is in the first quadrant.
Then sin x = opp / hyp = 5/13 (answer)
cos 2 is an entirely different kind of problem. Here you are told what the argument (input) to the cosine function is (it is 2, which here means 2 radians).
Using a calculator: cos 2 = -0.416. Note that the angle 2 rad is in QII, which is why the "adjacent side" is negative and also why the cos of 2 is negative.
There least common factor would be 5 since they are all divisible by 5.
Answer: 130 ft
Step-by-step explanation:
a^2 + b^2 = c^2
Where a and b are the legs that form the right angle and c is the hypotenuse (the side directly opposite of the right angle)
50^2 + 120^2 = c ^2
2,500 + 14,400 = c^2
16,900 = c^2
Take the square root of 16,900 to get c.
C = 130
Hypotenuse length is 130
Answer:
The answer is no.d b= 2a + 1
The y intercept is 3
You can also say that the y intercept is at (0,3) which is a more detailed answer. However saying "y intercept is 3" is sufficient enough because the x coordinate of the y intercept is always x = 0.
The y intercept is the location where the graph crosses or touches the y axis. This is at the halfway point between the 2 and 4, so (2+4)/2 = 6/2 = 3
