The solution to this problem is y raised to the 4th power.
The desired measures for the data-set is given by:
<h3>How to find the five number summary and interquartile range of the data-set?</h3>
The five number summary is composed by the measures explained below, except the IQR.
- The minimum value is the smallest value from the data-set, as the maximum value is the greatest value of the data-set.
- The median of the data-set separates the bottom half from the upper half, that is, it is the 50th percentile.
- The first quartile is the median of the first half of the data-set.
- The third quartile is the median of the second half of the data-set.
- The interquartile range is the difference of the third quartile and the first quartile.
In this problem, we have that:
- The minimum value is the smallest value, of 48.
- The maximum value is the smallest value, of 80.
- The data-set has even cardinality, hence the median is the mean of the middle elements, which are 63 and 64, hence the median is of 63.5.
- The first quartile is the median of the five elements of the first half, hence it is of 54.
- The third quartile is the median of the five elements of the second half, hence it is of 74.
- The IQR is the difference between the quartiles, hence 74 - 54 = 20.
More can be learned about five number summaries at brainly.com/question/17110151
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After 8 minutes it would be 2000, so after 16 it would be 4000
Answer:
need more info
Step-by-step explanation:
Answer:
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 64
Sample mean = 22.3
Sample standard deviation = 8.8
We want to estimate 92% confidence interval.
92% Confidence interval:
Putting the values, we get,
Degree of freedom = n - 1 = 63