12 touchdowns in 6 games unit rate

2 answers:

7 0

Hey there!

To find the unit rate of touchdowns per game, start with this proportion where x is the amount of touchdowns:
$\frac{12}{6}$ = $\frac{x}{1}$

Now, cross multiply:
12=6x

Divide both sides to solve for x:
12/6=6x/6
x=2

Therefore, you have 2 touchdowns for every game or 2/1.

Ulleksa [173]3 years ago

4 0

If you make it a ratio, it will be 12:6 which is reduced to 2:1.

You might be interested in

You want to obtain a sample to estimate a population proportion. At this point in time, you have no reasonable preliminary estim

pogonyaev

Answer:

$n=\frac{0.5(1-0.5)}{(\frac{0.025}{1.28})^2}=655.36$

And rounded up we have that n=656

Step-by-step explanation:

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 80% of confidence, our significance level would be given by $\alpha=1-0.80=0.20$ and $\alpha/2 =0.10$ . And the critical value would be given by:

$z_{\alpha/2}=\pm 1.28$

Solution to the problem

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

Since we don't have prior info for the proportion of interest we can use $\hat p=0.5$ as estimator. And on this case we have that $ME =\pm 0.025$ and we are interested in order to find the value of n, if we solve n from equation (a) we got: