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Hoochie [10]
3 years ago
9

What is the answer for the second one? 7% is the same as ??

Mathematics
1 answer:
ipn [44]3 years ago
8 0

Answer:

0.07

Step-by-step explanation:

Just put the value of the percent

40, 90, or 7 over 100

40/100, 90/100, 7/100

This yields

0.4, 0.9, 0.07

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Can someone help me with these two questions?
fenix001 [56]

Answer:

17) A(-1,1) B(-1,4) C(5,1)

18) (From origin moving rightwards)

     A(0,0) B(a, 0) C(a,a) D(0,a)

Step-by-step explanation:

17) You just count the steps, how many steps left, right, up, or down

18) The first point is at the origin, so 0,0

    The second point that lies on the x axis is (a,0) as it is a distance from the origin, 0 because it's on the x-axis.

     The third point is (a,a) because it is a distance to the right of the origin AND a distance upwards from the x axis.

      The fourth point (0,a) because it is on the vertical line (0) and is a distance above the origin.

5 0
3 years ago
At 2 PM there were 13 seagulls on the beach. At 5 PM there were 70 seagulls. What is the constant rate of change
Olin [163]
The answer is 57 I hope I helped
8 0
3 years ago
Austin buys $10 worth of food for his dog each week. There are 52 weeks in a year.
ololo11 [35]

Answer:

b i think

Step-by-step explanation:

8 0
3 years ago
A mass of 5 kg stretches a spring 10 cm. The mass is acted on by an external force of 10sin( t ) N(newtons) and moves in a mediu
yKpoI14uk [10]

Answer:

A) C1 = 0.00187 m = 0.187 cm,  C2 = 0.0062 m = 0.62 cm

B)  A sample of how the graph looks like is attached below ( periodic sine wave )

C) w = \sqrt[4]{3} is when the amplitude of the forced response is maximum

Step-by-step explanation:

Given data :

mass = 5kg

length of spring = 10 cm = 0.1 m

f(t) = 10sin(t) N

viscous force = 2 N

speed of mass = 4 cm/s = 0.04 m/s

initial velocity = 3 cm/s = 0.03 m/s

Formulating initial value problem

y = viscous force / speed = 2 N / 0.04 m/s = 50 N sec/m

spring constant = mg/ Length of spring = (5 * 9.8) / 0.1 = 490 N/m

f(t) = 10sin(t/2) N

using the initial conditions of u(0) = 0 m and u"(0) = 0.03 m/s to express the equation of motion

the equation of motion = 5u" + 50u' + 490u = 10sin(t/2)

A) finding the solution of the initial value

attached below is the solution and

B) attached is a periodic sine wave replica of how the grapgh of the steady state solution looks like

C attached below

3 0
3 years ago
Follow this link to view Juan's work. Critique Juan's work by justifying correct solutions and by explaining any errors he made
Aleksandr [31]

Answer:

I don't no sorry please bro sorry

4 0
3 years ago
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