I believe you would create and equation to find x and y.
The number 49 is a rational number because it can be expressed as the quotient of two integers; 49 divided by 1
Answer:
4
Step-by-step explanation:
r^-7*r^4=r^-7+4=r^-3=1/r^3
Given: The side of a square is (3x - 6) units.
Note that (a + b)² = a² + 2ab + b².
Part A
The area of the square is
A = (3x - 6)(3x - 6)
= (3x)² + 2(3x)(-6) + (-6)²
= 9x² - 36x + 36
Part B
The area is a 2nd-degree polynomial, or a quadratic function, or parabola.
Part C
A 2nd-degree polynomial is of the form
f(x) = ax² + bx¹ + cx⁰ = ax² + bx + c
where a,b,c are constants (coefficients of the polynomial).
The area obtained in Part A has the coefficients
a = 9, b = -36, c = 36.
The polynomial is closed because it is completely defined by multiply and addition operations.
So it goes as
8x+4y=16
7y=15-x
I want x by itself in the second equation so I subtracted 15 from both sides
7y-15=-x
I then divided each side by -1 to get
x=-7y+15
Now that I have x, I can plug that into the first equation to get:
8(-7y+15)+4y=16
Factor:
-56y+120+4y=16
Combine like terms and subtract both sides by 120
-52y=-104
Divide both sides by -52 to get y by itself
y=2
Therefore, the coordinates are (1,2) or C .
