(Question is in the image)<br><br> please I really need help

Uma abelha rainha dividiu as abelhas de sua comeia nos seguintes grupos para exploração ambiental: um composto de 288 batedoras

sergeinik [125]

Groups of four for the group of 288 and groups of five for the group of 360

7 0

2 years ago

Plzzzz answer question 14

viktelen [127]

Its D because when you use some graph paper point A and point B are 6 units away from each other

6 0

3 years ago

Consider a chemical company that wishes to determine whether a new catalyst, catalyst XA-100, changes the mean hourly yield of i

kolezko [41]

Answer:

Null hypothesis: $\mu = 750$

Alternative hypothesis: $\mu \neq 750$

$t=\frac{811-750}{\frac{19.647}{\sqrt{5}}}=6.943$

$p_v =2*P(t_{4}>6.943)=0.00226$

If we compare the p value and a significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the actual true mean is significantly different from 750 pounds per hour.

Step-by-step explanation:

Data given and notation

Data: 801, 814, 784, 836,820

We can calculate the sample mean and sample deviation with the following formulas:

$\bar X =\frac{\sum_{i=1}^n X_i}{n}$

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X=811$ represent the sample mean

$s=19.647$ represent the standard deviation for the sample

$n=5$ sample size

$\mu_o =750$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses to be tested

We need to conduct a hypothesis in order to determine if the mean is different from 750 pounds per hour, the system of hypothesis would be:

Null hypothesis: $\mu = 750$

Alternative hypothesis: $\mu \neq 750$

Compute the test statistic

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

We can replace in formula (1) the info given like this:

$t=\frac{811-750}{\frac{19.647}{\sqrt{5}}}=6.943$

Now we need to find the degrees of freedom for the t distirbution given by:

$df=n-1=5-1=4$

What do you conclude?

Compute the p-value

Since is a two tailed test the p value would be:

$p_v =2*P(t_{4}>6.943)=0.00226$

If we compare the p value and a significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the actual true mean is significantly different from 750 pounds per hour.

4 0

3 years ago

Select strong association, weak association, or moderate association to correctly classify the correlation coefficient.

11Alexandr11 [23.1K]

Answers:

0.45 is a moderate association

0.95 and -0.8 are both strong association

0.10 is weak association

Explanation:

This is the interpreation of the correltaion coefficient:

1) The correlaion coefficient assesses the relationship between two variables in a scatter plot.

2) If the sign of the correlation coefficient is positive means that the two variables trend to grow or decrease in the same sense. This is an uphill line or curve: if variable X grows, variable Y grows, and if variable X decreases variable Y grows.

If the sign of the correlation coefficient is negative means that the two variables go in opposite direction. This is a downhill line or curve.

3) A correlation coefficient of +1 or -1 is a perfect association. The two variables are totally associated.

4) A correlation coefficient less that +1 but greater than 0.7 is a strong association. The same with a coefficite between - 0.7 and -1.

5) A correlation coefficient arroun +0.5 or -0.5 is a moderate association.

6) A correlation coefficient of 0 is a nill association.

7) A correlation coeffiicient between 0 and 0.3 is a weak association. The same when the correlation coefficient is between -3 and 0.

4 0

3 years ago

Read 2 more answers

Help please I’m trying to go to sleep

Varvara68 [4.7K]

Answer: y > -4 (red)

Step-by-step explanation:

6 0

3 years ago

(Question is in the image) please I really need help