Hi! I'm happy to help!
Our total line is JL (4x), and it is split into two parts: JK, and KL. We have our values, and we know that JK+KL=JL, so we can substitute our values and solve for x:
4x=(2x+3)+(x)
4x=3x+3
To solve for x, we have to isolate it on one side of the equation.
First, let's subtract 3x from both sides so that we can isolate x:
4x=3x+3
-3x -3x
x=3
<u>So, our x=3, which means that KL=3.</u>
I hope this was helpful, keep learning! :D
Answer: 693
it is 693 because...
I couldn't really explain with words so I gave you a step by step of my work.
Number 1 is x=8!!
2 is pretty confusing so I hope someone else can answer two as I have answered 1!
Answer:
I ant help you but, my sister can ill get her
Step-by-step explanation:
This problem can be readily solved if we are familiar with the point-slope form of straight lines:
y-y0=m(x-x0) ...................................(1)
where
m=slope of line
(x0,y0) is a point through which the line passes.
We know that the line passes through A(3,-6), B(1,2)
All options have a slope of -4, so that should not be a problem. In fact, if we check the slope=(yb-ya)/(xb-xa), we do find that the slope m=-4.
So we can check which line passes through which point:
a. y+6=-4(x-3)
Rearrange to the form of equation (1) above,
y-(-6)=-4(x-3) means that line passes through A(3,-6) => ok
b. y-1=-4(x-2) means line passes through (2,1), which is neither A nor B
****** this equation is not the line passing through A & B *****
c. y=-4x+6 subtract 2 from both sides (to make the y-coordinate 2)
y-2 = -4x+4, rearrange
y-2 = -4(x-1)
which means that it passes through B(1,2), so ok
d. y-2=-4(x-1)
this is the same as the previous equation, so it passes through B(1,2),
this equation is ok.
Answer: the equation y-1=-4(x-2) does NOT pass through both A and B.
