PART A:
Finding the slope of the function f(x)
Choose any two pairs of coordinate from the table; (-1, -15) and (0, -10)
Let (-1, -15) be (x₁, y₁) and (0, -10) be (x₂, y₂)
Slope =
Slope of f(x) = 5
The function g(x) is given in the straight line equation form
Where, is the slope and is the y-intercept
Slope of g(x) = 2
-----------------------------------------------------------------------------------------------------------
g(x) = 2x + 8
Where, the slope (m) = 2 and the y-intercept (c) = 8
The y-intercept of g(x) is 8
for f(x), we can read the y-intercept when x = 0.
From the table, when x = 0, y = -10
The y-intercept of f(x) is -10
Function g(x) has higher y-intercept
Which data set has an outlier? 25, 36, 44, 51, 62, 77 3, 3, 3, 7, 9, 9, 10, 14 8, 17, 18, 20, 20, 21, 23, 26, 31, 39 63, 65, 66,
umka21 [38]
It's hard to tell where one set ends and the next starts. I think it's
A. 25, 36, 44, 51, 62, 77
B. 3, 3, 3, 7, 9, 9, 10, 14
C. 8, 17, 18, 20, 20, 21, 23, 26, 31, 39
D. 63, 65, 66, 69, 71, 78, 80, 81, 82, 82
Let's go through them.
A. 25, 36, 44, 51, 62, 77
That looks OK, standard deviation around 20, mean around 50, points with 2 standard deviations of the mean.
B. 3, 3, 3, 7, 9, 9, 10, 14
Average around 7, sigma around 4, within 2 sigma, seems ok.
C. 8, 17, 18, 20, 20, 21, 23, 26, 31, 39
Average around 20, sigma around 8, that 39 is hanging out there past two sigma. Let's reserve judgement and compare to the next one.
D. 63, 65, 66, 69, 71, 78, 80, 81, 82, 82
Average around 74, sigma 8, seems very tight.
I guess we conclude C has the outlier 39. That one doesn't seem like much of an outlier to me; I was looking for a lone point hanging out at five or six sigma.
