Answer:
x^2+y^2 = 3^2
Step-by-step explanation:
We need to eliminate the parameter t
Given:
x = 3 cos t
y = 3 sin t
Squaring the above both equations
(x)^2=(3 cos t)^2
(y)^2 =(3 sin t)^2
x^2 = 3^2 cos^2t
y^2=3^2 sin^2t
Now adding both equations
x^2+y^2=3^2 cos^2t+3^2 sin^2t
Taking 3^2 common
x^2+y^2=3^2 (cos^2t+sin^2t)
We know that cos^2t+sin^2t = 1
so, putting the value
x^2+y^2=3^2(1)
x^2+y^2 = 3^2
Hence the parameter t is eliminated.
2x^2 + 8x = 0
2x(× + 4) = 0
2x = 0
x = 0/2 =0
x + 4 = 0
x = -4
Answer:
6.0435*10²⁴
Step-by-step explanation:
Moon: 7.35*10²²
Earth: 5.97*10²⁴
7.35*10²² = 0.0735*10²⁴
then:
0.0735*10²⁴ + 5.97*10²⁴ = (0.0735 + 5.97)*10²⁴
= 6.0435 *10²⁴
Answer:
<em>hey </em>
Step-by-step explanation:
which u r studying inn
2x² - 128
2(x² - 64), but (x² - 64) = x² - 8² (difference of 2 squares),[a²-b²=(a-b)(a+b)]
2(x² - 64) = 2(x² - 8²) = 2(x-8)(x+8)
