First the y-intercept would increase. The magnitude of the slope of the trendline would decrease as compared to the slope with all the years in them. The slope would still be increasing. And there would still be a positive correlation.
10(9+8t)
10x9+10x8t
90+8t
hope that helps
When 
![t=\cos A+\sin A\in[-\sqrt{2};\sqrt{2}]\approx[-1.4142;1.4142]](https://tex.z-dn.net/?f=%20t%3D%5Ccos%20A%2B%5Csin%20A%5Cin%5B-%5Csqrt%7B2%7D%3B%5Csqrt%7B2%7D%5D%5Capprox%5B-1.4142%3B1.4142%5D%20)
and there is only one answer t = 1.
For 
both values are correct.
Answer:
B
Step-by-step explanation:
it's basically 2+7
48/5 or 9 3/5
12.8/1 x 3/4 = 38.4/4
Or multiply 12.8/1 by 10 ==> 128/10
128/10 x 3/4 = 384/40
Hope this helps!
