Answer:
- 5.8206 cm
- 10.528 cm
- 23.056 cm^2
Step-by-step explanation:
(a) The Law of Sines can be used to find BD.
BD/sin(48°) = BD/sin(50°)
BD = (6 cm)(sin(48°)/sin(60°)) ≈ 5.82064 cm
__
(b) We can use the Law of Cosines to find AD.
AD^2 = AB^2 +BD^2 -2·AB·BD·cos(98°) . . . . . angle ABD = 48°+50°
AD^2 ≈ 110.841
AD ≈ √110.841 ≈ 10.5281 . . . cm
__
(c) The area of ∆ABD can be found using the formula ...
A = ab·sin(θ)/2 . . . . . where a=AB, b=BD, θ = 98°
A = (8 cm)(5.82064 cm)sin(98°)/2 ≈ 23.0560 cm^2
_____
Angle ABD is the external angle of ∆BCD that is the sum of the remote interior angles BCD and BDC. Hence ∠ABD = 48° +50° = 98°.
Answer:
b<-21
Step-by-step explanation:
1/3b+1<-6
1/3b<-7
*3 *3
b<-21
Answer:
n+3
Step-by-step explanation:
the relationship between those numbers are consistently adding 3 thus n +3
Hope this helps lozzzzzzs
First, set the equation in exponential form.
x=logbY to b^x=Y
x=log44. so x=x, b=10, Y=44
10^x=44
I know that 10^1=10, 10^2=100, and 10^1.5=31.6 so x should be between 1.5 and 2.
The answer is x=1.64.
