the volume of the triangular prism will be, the area of the triangular face times its length
![\stackrel{\textit{area of the triangle}}{\left[ \cfrac{1}{2}(\underset{b}{8})(\underset{h}{8}) \right]}~~ ~~\stackrel{length}{(x)}~~ = ~~\stackrel{volume}{576}\implies 32(x)=576 \\\\\\ 32x=576\implies x=\cfrac{576}{32}\implies x=18](https://tex.z-dn.net/?f=%5Cstackrel%7B%5Ctextit%7Barea%20of%20the%20triangle%7D%7D%7B%5Cleft%5B%20%5Ccfrac%7B1%7D%7B2%7D%28%5Cunderset%7Bb%7D%7B8%7D%29%28%5Cunderset%7Bh%7D%7B8%7D%29%20%5Cright%5D%7D~~%20~~%5Cstackrel%7Blength%7D%7B%28x%29%7D~~%20%3D%20~~%5Cstackrel%7Bvolume%7D%7B576%7D%5Cimplies%2032%28x%29%3D576%20%5C%5C%5C%5C%5C%5C%2032x%3D576%5Cimplies%20x%3D%5Ccfrac%7B576%7D%7B32%7D%5Cimplies%20x%3D18)
According to my math, there are approximately 2557.179 millilitres in 90 ounces.
Answer:
5.83 units
Step-by-step explanation:
See attached picture. You can use the Pythagorean Theorem. I added some lines to show the legs of a right triangle. AB is the hypotenuse.
<em>No</em>. For all the things that humans are really good at, picking totally random numbers is not one of them. There are certain numbers that people are more likely to consider "random" than others; for instance, odd numbers and prime numbers tend to be popular picks as far as "random-looking" numbers go, and this trend can make so-called "random" picks a lot less random that we'd like them to be.
To get a truly random sample, using a <em>random number generator</em>, especially a <em>truly random </em>number generator, will give you a truly random sample.
I'm pretty sure it say "what percentage of £16 is 40p
x/100 *16 = 0.40
0.16x=0.40
0.40/0.16= 2.5
2.5% of £16 is 0.40p
