Answer:
The large number is 31, and the small number is 16
Step-by-step explanation:
Given data
let the first number be x
and the second number be y
so
x+y= 47------------1
and
y-x= 15-------------2
from eqn1
x= 47-y
put this in eqn 2
y-(47-y)=15
y-47+y=15
2y= 15+47
2y=62
divide both side by 2
x= 62/2
x=31
From eqn 1
x+y= 47
31+y=47
y=47-31
y=16
Here’s how to solve it:
1. Multiply the fraction by √6/√6
2. To multiply the fractions, multiply the numerators and denominators separately
3. When a square root of an expression is multiplied by itself, the result is that equation
4. Reduce the fraction with 2
5. Answer is below
Answer:
[-4,2] or 
Step-by-step explanation:
Range is the range of the y-axis.
Although we see that the "line" ends at a specific point, it is neither the highest or lowest y-value.
Our lowest y value is -4, and because it is a line, it is not an open dot resulting in a [, instead of a (.
This same thing happens with highest y-value which happens to be 2.
This is interval notation.
Due to your question, you may be asking for this:

Answer:
I haven done that in a hot minute. jeezzz
Step-by-step explanation: