Answer:
Yes, any number that can be written as a fraction is a rational number.
Step-by-step explanation:
Answer:
![\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]*\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]=\left[\begin{array}{ccc}5\\6\\7\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%265%5C%5C1%261%261%5C%5C4%266%265%5Cend%7Barray%7D%5Cright%5D%2A%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx1%5C%5Cx2%5C%5Cx3%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%5C%5C6%5C%5C7%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
Let's find the answer.
Because we have 3 equations and 3 variables (x1, x2, x3) a 3x3 matrix (A) can be constructed by using their respectively coefficients.
Equations:
Eq. 1 : x1 + 2x2 + 5x3 = 5
Eq. 2 : x1 + x2 + x3 = 6
E1. 3 : 4x1 + 6x2 + 5x3 = 7
Coefficients for x1 ; x2 ; x3
From eq. 1 : 1 ; 2 ; 5
From eq. 2 : 1 ; 1 ; 1
From eq. 3 : 4 ; 6 ; 5
So matrix A is:
![\left[\begin{array}{ccc}1&2&5\\1&1&1\\4&6&5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%262%265%5C%5C1%261%261%5C%5C4%266%265%5Cend%7Barray%7D%5Cright%5D)
And the vector of vriables (X) is:
![\left[\begin{array}{ccc}x1\\x2\\x3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx1%5C%5Cx2%5C%5Cx3%5Cend%7Barray%7D%5Cright%5D)
Now we can find the resulting vector (B) using the 'resulting values' from each equation:
![\left[\begin{array}{ccc}5\\6\\7\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%5C%5C6%5C%5C7%5Cend%7Barray%7D%5Cright%5D)
In conclusion, AX=B is:
For a data point measured as y = 3.5 for an x value of x = 1.2, the residual would be 0.1
For given question,
we have been given an equation 2x + 1 that represents an equation for a trendline to the data.
General formula with residual is y = 2x + 1 + r, where r is a residual.
We need to find the residual for a data point measured as y = 3.5 for an x value of x = 1.2
We substitute given values of x and y in the residual equation
y = 2x + 1 + r
For y = 3.5 and x = 1.2,
⇒ 3.5 = 2(1.2) + 1 + r
⇒ 3.5 = 2.4 + 1 + r
⇒ r = 3.5 - 3.4
⇒ r = 0.1
Therefore, for a data point measured as y = 3.5 for an x value of x = 1.2, the residual would be 0.1
Learn more about the residual here:
brainly.com/question/10228420
#SPJ4
Given:
First, let's move the -1 to the right side. When we add 
, we get 
.
Now we can cross multiply, multiply (3n)(8) and (7)(9)
Simplify the left side.
Simplify the right side.
Divide both sides by 24 to isolate n.
Simplify.
Answer:
r = 9/sin Ф or r = 9 csc Ф
Step-by-step explanation:
The polar form is represented as:
x = r cos Ф and
y = r sin Ф
We are given:
y = 9
Putting value in y = r sin Ф
9 = r sin Ф
=> r = 9/sin Ф
1/sin Ф = csc Ф
or, r = 9 csc Ф
