Triangle P Q R is shown. The length of P Q is 17, the length of Q R is 15, and the length of P R is 14. Law of cosines: a2 = b2
+ c2 – 2bccos(A) What is the measure of AngleP to the nearest whole degree? 35° 52° 57° 72°
1 answer:
Answer:
P = 57°
Step-by-step explanation:
Given the following :
PQ = 17
QR = 15
PR = 14
Using the cosine formula since the length of the three sides are given:
a2 = b2 + c2 – 2bccos(A)
To find P:
QR^2 = PQ^2 + PR^2 – 2(PQ)(PR)cos(P)
15^2 = 17^2 + 14^2 – 2(17)(14)cos(P)
225 = 289 + 196 - 476 cosP
476*CosP = 485 - 225
476*CosP = 260
CosP = 260/476
CosP = 0.5462184
P = Cos^-1(0.5462184)
P = 56.892029
P = 57°
You might be interested in
Answer:
x=2
Step-by-step explanation:
-3 = -2x +1
+3 +2x = +2x +3
2x=4
divide them both by 2
x=2
Sorry... you probably don't need the answer now but It is d...
I don't know who reported the last person but they are correct
After I answer this, can you answer my question
182,040-164,000 that’s the answer YOUR WELCOME
Y = -4x +5 should be right!