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Bas_tet [7]
4 years ago
10

Is it possible to construct a regular hexagon using only a straightedge and a compass?

Mathematics
2 answers:
Mashcka [7]4 years ago
8 0
Yes, it is possible to construct a regular hexagon with a straight edge and compass I did it in my geometry class.
Cloud [144]4 years ago
5 0

Answer:

Yes

Step-by-step explanation:

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Using the distance formula, d = √(x2 - x1)2 + (y2 - y1)2, what is the distance between point (0, 5) and point (3, -1) rounded to
miss Akunina [59]

\sqrt{(3-0)^2+(-1-5)^2}=\sqrt{3^2+(-6)^2}=\sqrt{45}\approx 6.7

answer (a)

5 0
3 years ago
If there are 15 boys and 18 girls in seventh grade. Find the ratio of boys to girls -- and simplify it.
Veseljchak [2.6K]

Ratio of boys to the girls

= No of boys ÷ No of girls

=15÷18

=5:6

4 0
3 years ago
Write the equation of the line that passes through the points (2, 5) and (3, 10)
stira [4]
It would be y=5.00x + -5.00
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In UVW, u = 190 cm, v = 380 cm and w=560 cm. Find the measure of ZW to the
disa [49]

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157.2

Step-by-step explanation:

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6 0
3 years ago
Read 2 more answers
Read it and solve it for me
AnnyKZ [126]

Answer:

a. y + 9 + x + y + x + 4 + x + 5 = 2x + 2y + 18

b. 30.4cm

c. Area of big rectangle = 9y cm², Area of small rectangle = 4x cm²

d. a = 9y + 4x

e. a = 38.8

Step-by-step explanation:

a. Perimeter = y + 9 + x + y + x + 4 + x + 5

                     = x + x + y + y + 9 + 4 + 5

                     = 2x + 2y + 18

b. 2x + 2y + 18 = 2(3.4) + 2(2.8) + 18

                        = 6.8 + 5.6 + 18

                        = 30.4cm

c. Formula for area of rectangle: length × breadth

Area of big rectangle = 9 × y

                                    = 9y cm²

Area of small rectangle = 4 × x

                                       = 4x cm²

d. a cm² = (9y + 4x)cm²

e. a = 9y + 4x

      = 9(2.8) + 4(3.4)

      = 25.2 + 13.6

      = 38.8

4 0
3 years ago
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