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kupik [55]
3 years ago
9

6 cm

Mathematics
2 answers:
evablogger [386]3 years ago
7 0

Answer:

1,590.02

just round it to the nearest centimeter

Step-by-step explanation:

BigorU [14]3 years ago
3 0
What the first person said and have a good night
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Maristella is constructing an isosceles triangle to use as a model in her Algebra class. The perimeter of her triangle is 24 cm.
Vlada [557]

Isolating s, the equation written in terms of s is:

s = 12 - 0.5b

-------------------------

  • The equation for the length of the third side, as stated in the problem,("Maristella uses the equation b = 24 – 2s to find b, the length of the triangle's third side") is:

b = 24 - 2s

  • To solve for the lengths of the congruent sides, we isolate s, thus:

b = 24 - 2s

2s = 24 - b

Inverse of multiplication is division, thus:

s = \frac{24 - b}{2}

Separating into two fractions:

s = \frac{24}{2} - \frac{b}{2}

Solving each fraction:

s = 12 - 0.5b

A similar problem is given at brainly.com/question/5123313

3 0
3 years ago
The equation 116 = -7(4 - 2p) + 4p<br> is equivalent to which of the following?
Alexxx [7]

Answer:

d

Step-by-step explanation:

You distribute -7 into (4-2p) and then combine like terms to get 116=-28-18p

4 0
3 years ago
Need help , if you can answer it pls do . thank you
lara [203]

Answer:

9

Step-by-step explanation:

14-5=9

therefore TV=9

hope this helped

3 0
3 years ago
Given sec(theta)= 5... find cot(90-theta)
Mumz [18]
\sec(\theta)=\frac{1}{\cos(\theta)}&#10;\\&#10;\\\cos(\theta)=\frac{1}{\sec(\theta)}=\frac{1}{5}&#10;\\&#10;\\ \sin^2\theta+\cos^2\theta=1&#10;\\&#10;\\\sin\theta= \sqrt{1-\cos^2\theta}= \sqrt{1-( \frac{1}{5})^2 }  = \sqrt{1- \frac{1}{25} } = \sqrt{ \frac{25}{25} -\frac{1}{25} }=\frac { \sqrt{24}}{5} &#10;\\&#10;\\ \cot(90^o-\theta)=\tan{\theta}= \frac{\sin\theta}{\cos\theta} = \frac{\frac { \sqrt{24}}{5} }{ \frac{1}{5} } = \sqrt{24} = \sqrt{4\times6}=2 \sqrt{6}  &#10;\\&#10;
3 0
3 years ago
Need help with this question ​
Andreas93 [3]

The Domain is (-∞, -2) U (-2, 2) U (2, ∞) and Range is (-∞, -2) U [-1, ∞) and x-intercept = (-1.5, 0), (1.5, 0) and y-intercept = (0, -1).

<h3>What is a conic section?</h3>

It is defined as the curve which is the intersection of cone and plane. There are three major conic sections; parabola, hyperbola, and ellipse (circle is a special of type of ellipse).

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

From the graph:

a) The domain: all values of x

The range: all values of y

Except: Values at asymptotes are excluded.

Domain = (-∞, -2) U (-2, 2) U (2, ∞)

Range = (-∞, -2) U [-1, ∞)

b)

x-intercept = (-1.5, 0), (1.5, 0)

y-intercept = (0, -1)

c) Horiznotal asymptotes: y = -2

d)Vetical asymptotes: x = -2, x = 2

e) Oblique asymptotes: There is no oblique asymptotes

Thus, the Domain is (-∞, -2) U (-2, 2) U (2, ∞) and Range is (-∞, -2) U [-1, ∞) and x-intercept = (-1.5, 0), (1.5, 0) and y-intercept = (0, -1).

Learn more about the conic section here:

brainly.com/question/8412465

#SPJ1

7 0
2 years ago
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