<u>Answer:</u>
<em><u>w = -19</u></em>
<em><u></u></em>
<u>Explanation:</u>
To solve this equation, subtract ten from both sides. This will isolate the variable (w) and allow us to find its value.
If you would like to double check that the variable (w) does in fact equal negative nineteen, substitute the value of the variable in the equation and solve.
![10 + w = -9\\10 + -19 = -9\\-19 = -19 [true]](https://tex.z-dn.net/?f=10%20%2B%20w%20%3D%20-9%5C%5C10%20%2B%20-19%20%3D%20-9%5C%5C-19%20%3D%20-19%20%5Btrue%5D)
Therefore, the value of w in the given equation is <em><u>-19.</u></em>
Your answer would be B because even though it's the same shape the red shape is 2 times bigger.......your exponent 4 stays 4
5x+12=37
X=5
Hope u do well on the test
Pair up the terms into separate groups. Then factor each group individually (pull out the GCF). Once that is finished, you factor out the overall GCF to complete the full factorization.
8r^3 - 64r^2 + r - 8
(8r^3 - 64r^2) + (r - 8)
8r^2(r - 8) + (r - 8)
8r^2(r - 8) + 1(r - 8)
(8r^2 + 1)(r - 8)
So the final answer is (8r^2 + 1)(r - 8)
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Edit:
Problem 1b) Follow the same basic steps as in part A
28v^3 + 16v^2 - 21v - 12
(28v^3 + 16v^2) + (-21v - 12)
4v^2(7v + 4) + (-21v - 12)
4v^2(7v + 4) - 3(7v + 4)
(4v^2 - 3)(7v + 4)
The answer to part B is (4v^2 - 3)(7v + 4)
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Second Edit:
I apologize for the first edit. I misread what you were asking initially. Here is problem 2A. We follow the same basic steps as in 1a) and 1b). You'll need to rearrange terms first
27mz - 12nc + 9mc - 36nz
27mz + 9mc - 12nc - 36nz
(27mz + 9mc) + (-12nc - 36nz)
9m(3z + c) + (-12nc - 36nz)
9m(3z + c) -12n(c + 3z)
9m(3z + c) -12n(3z + c)
(9m - 12n)(3z + c)
3(3m - 4n)(3z + c)
Question:
What is the value of 
when x=3 and y=0
Answer:
The answer is zero
Step-by-step explanation:
Given:
x = 3
y = 0
Solution:
Let us first substitute the given values inb the expression
then we get
We also know that anything raised to the power of zero also give zero
then
=> 0
