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Veronika [31]
2 years ago
7

-4(6-b)=4 show work plz

Mathematics
1 answer:
igomit [66]2 years ago
7 0

Answer:

b= 7

Step-by-step explanation:

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Write 7,258,630 in word form
bixtya [17]
Seven million two hundred
ed fifty eight thousand six hundred
thirty
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3 years ago
How many different four-person relay team can recover from a student
prohojiy [21]
Well, You have 4  students and 8 other students. If theres 8 people, this means theres 8 combinations possible. This means you do 8x4 and you get 32.
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3 years ago
Determine the location and values of the absolute maximum and absolute minimum for given function : f(x)=(‐x+2)4,where 0<×&lt
brilliants [131]

Answer:

Where 0 < x < 3

The location of the local minimum, is (2, 0)

The location of the local maximum is at (0, 16)

Step-by-step explanation:

The given function is f(x) = (x + 2)⁴

The range of the minimum = 0 < x < 3

At a local minimum/maximum values, we have;

f'(x) = \dfrac{(-x + 2)^4}{dx}  = -4 \cdot (-x + 2)^3 = 0

∴ (-x + 2)³ = 0

x = 2

f''(x) = \dfrac{ -4 \cdot (-x + 2)^3}{dx}  = -12 \cdot (-x + 2)^2

When x = 2, f''(2) = -12×(-2 + 2)² = 0 which gives a local minimum at x = 2

We have, f(2) = (-2 + 2)⁴ = 0

The location of the local minimum, is (2, 0)

Given that the minimum of the function is at x = 2, and the function is (-x + 2)⁴, the absolute local maximum will be at the maximum value of (-x + 2) for 0 < x < 3

When x = 0, -x + 2 = 0 + 2 = 2

Similarly, we have;

-x + 2 = 1, when x = 1

-x + 2 = 0, when x = 2

-x + 2 = -1, when x = 3

Therefore, the maximum value of -x + 2, is at x = 0 and the maximum value of the function where 0 < x < 3, is (0 + 2)⁴ = 16

The location of the local maximum is at (0, 16).

5 0
3 years ago
Solve -24 + (1-4)^2​
ElenaW [278]

Answer:

-15

Step-by-step explanation:

-24 + (1-4)^2​    (solve parentheses first)

= -24 + (-3)^2 (solve exponent)

= -24 + 9

= -15

6 0
3 years ago
Read 2 more answers
Hi whats the answer<br> √548
harkovskaia [24]
23.409399821439250218
6 0
3 years ago
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