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soldi70 [24.7K]
4 years ago
13

A teacher had 24 red pen.if the ratio of red pens to blue pens she owned was 8:7, how many pens did she have total

Mathematics
1 answer:
Nat2105 [25]4 years ago
7 0
Since it the ratio was 8:7
24 red pens=8, so 8 times 3 is 24. So 7 times 3 is 21. 21+24=45
Hope this helped <3
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Please help i keep getting the wrong answers
Mrrafil [7]

Answer:

10 inches

Step-by-step explanation:

Surface Area = π R² + π R L [ L is Slant Height ]

200 π = π (10)² + π (10) L

200 π = π (100) + π (10) L

200 π - 100 π = 10 π L

100 π = 10 π L

100 π / 10 π = L

10 = L

L = 10 inches

Hope this Helps......

3 0
3 years ago
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write three ratios that are equivalent to the one given:the ratio of right of right-handed students to left-handed students is 1
laila [671]
The three ratios that is equal to 18:4 are

9 : 2 if you divide 18 and 4 by 2
36 : 8 if you multiply 18 and 4 by 2
54 : 12 if you multiply 18 and 4 by 3

Hope this helps!!
7 0
4 years ago
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Solve the following equations: (a) x^11=13 mod 35 (b) x^5=3 mod 64
tino4ka555 [31]

a.

x^{11}=13\pmod{35}\implies\begin{cases}x^{11}\equiv13\equiv3\pmod5\\x^{11}\equiv13\equiv6\pmod7\end{cases}

By Fermat's little theorem, we have

x^{11}\equiv (x^5)^2x\equiv x^3\equiv3\pmod5

x^{11}\equiv x^7x^4\equiv x^5\equiv6\pmod 7

5 and 7 are both prime, so \varphi(5)=4 and \varphi(7)=6. By Euler's theorem, we get

x^4\equiv1\pmod5\implies x\equiv3^{-1}\equiv2\pmod5

x^6\equiv1\pmod7\impleis x\equiv6^{-1}\equiv6\pmod7

Now we can use the Chinese remainder theorem to solve for x. Start with

x=2\cdot7+5\cdot6

  • Taken mod 5, the second term vanishes and 14\equiv4\pmod5. Multiply by the inverse of 4 mod 5 (4), then by 2.

x=2\cdot7\cdot4\cdot2+5\cdot6

  • Taken mod 7, the first term vanishes and 30\equiv2\pmod7. Multiply by the inverse of 2 mod 7 (4), then by 6.

x=2\cdot7\cdot4\cdot2+5\cdot6\cdot4\cdot6

\implies x\equiv832\pmod{5\cdot7}\implies\boxed{x\equiv27\pmod{35}}

b.

x^5\equiv3\pmod{64}

We have \varphi(64)=32, so by Euler's theorem,

x^{32}\equiv1\pmod{64}

Now, raising both sides of the original congruence to the power of 6 gives

x^{30}\equiv3^6\equiv729\equiv25\pmod{64}

Then multiplying both sides by x^2 gives

x^{32}\equiv25x^2\equiv1\pmod{64}

so that x^2 is the inverse of 25 mod 64. To find this inverse, solve for y in 25y\equiv1\pmod{64}. Using the Euclidean algorithm, we have

64 = 2*25 + 14

25 = 1*14 + 11

14 = 1*11 + 3

11 = 3*3 + 2

3 = 1*2 + 1

=> 1 = 9*64 - 23*25

so that (-23)\cdot25\equiv1\pmod{64}\implies y=25^{-1}\equiv-23\equiv41\pmod{64}.

So we know

25x^2\equiv1\pmod{64}\implies x^2\equiv41\pmod{64}

Squaring both sides of this gives

x^4\equiv1681\equiv17\pmod{64}

and multiplying both sides by x tells us

x^5\equiv17x\equiv3\pmod{64}

Use the Euclidean algorithm to solve for x.

64 = 3*17 + 13

17 = 1*13 + 4

13 = 3*4 + 1

=> 1 = 4*64 - 15*17

so that (-15)\cdot17\equiv1\pmod{64}\implies17^{-1}\equiv-15\equiv49\pmod{64}, and so x\equiv147\pmod{64}\implies\boxed{x\equiv19\pmod{64}}

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3 years ago
G(n)=n^3+n<br> g(-3)<br> help!
Svetradugi [14.3K]
The question is simply asking you to evaluate the function for an input value of -3. Meaning we plug in -3 for all cases of n. (-3)^3 + (-3). This gives us -27 -3 which is -30. So g(-3)= -30
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3 years ago
3x^2-192=0<br><img src="https://tex.z-dn.net/?f=3%20%7Bx%7D%5E%7B2%7D%20%20-%20192%20%3D%200" id="TexFormula1" title="3 {x}^{2}
Murljashka [212]
3x^2-192=0
3x^2=192
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x=\pm \sqrt{64}
x=\pm 8

x=-8 and x=8 are the solutions

5 0
3 years ago
Read 2 more answers
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