I think you subtitute de 34 by x not sure
Answer:
(4y + 1)(2y + 1) -- Unfortunately I can't help with the grid part
Step-by-step explanation:
Multiply the a and c term (8 * 1) to get 8. Think of what factors of 8 would add up to your b term (6), which would be 4 and 2. Rewrite your equation as 8y^2 + 4y + 2y + 1 and consider one half at a time and factor them individually. For the left, that'd be 4y(2y + 1), and for the right, you can't factor anything so it's just 1(2y + 1). Check that the things inside the parentheses are the same, which they are, and add the things you factored out and multiply that by the part in the parentheses for (4y + 1)(2y + 1).
Answer: 40
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Notice how WI = 12 is one-third of IL = 36
So AM is going to be one-third of ML = 30 making AM = 10
AL = AM+ML = 10+30 = 40
AL = 40
Or a more formal way to do it is to use ratios
AL/ML = WL/IL
AL/ML = (WI+IL)/IL
AL/30 = (12+36)/36
AL/30 = 48/36
36*AL = 30*48
36*AL = 1440
AL = 1440/36
AL = 40
Either way we get the same answer
Answer:
B. (8-9)(x) = x2 + 4x+ 3
Step-by-step explanation: Hi there! So the question is what is (f-g)(x)?
So let's start off with what is f(x) and g(x)?
f(x) is 2x²-5 while g(x) is x²-4x-8
So how do we do this? We subtract the two!
2x²-5 - (x²-4x-8) let's look at the g(x) function
-(x²-4x-8) (let's break it apart!
-(x²)= -x² -(-4x) = +4x -(-8)= +8 => -x²+4x+8 replace the original with the new for the problem
2x²-5-x²+4x+8 alrighty we have that the first thing to do is to combine like terms. Is there anything number or vairable that are the same? yes there is!
We see a 2x² and a negative x² => 2x²-x² would equal to x²
Next we see an -5 and a positive 8 => -5+8 equals to 3
Lastly, we have 4x. Where the other x variable? That's the thing? There is no. So in this case 4x is all alone.
With the answers we need to put them together. We would have...
x²+ 4x +3. That is the answer to (f-g)(x) in other words B.
Sorry about typing a lot. I love to explain in details lol. But if you have any questions or comments please don't be afraid to say anything! I really do hope I helped in any kind of way. Have a great day! :D
