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3 years ago

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The Mad Hat Company must ship two different-sized boxes: The small ones cost them 45 cents each and weigh 6 ounces, and the larg

e ones weigh 25 ounces and cost $1.20 each. The total shipment this morning weighed 20 pounds 7 ounces and cost $18.45. How many packages of each size were shipped?

1 answer:

Viefleur [7K]3 years ago

6 0

Given :

The Mad Hat Company must ship two different-sized boxes: The small ones cost them 45 cents each and weigh 6 ounces, and the large ones weigh 25 ounces and cost $1.20 each.

The total shipment this morning weighed 20 pounds 7 ounces and cost $18.45.

To Find :

How many packages of each size were shipped.

Solution :

We know, 1 pound = 16 ounces.

So, 20 pound = 20×16 = 320 ounces.

Let, number of large and small box are l and s.

So,

25l + 6s = 327 ...1)

0.45s + 1.20l = 18.45 ...2)

Solving both the equations, we get :

x = 9 and y = 17

Therefore, package smaller and big size are 17 and 9 respectively .

Hence, this is the required solution.

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None of the expression are equivalent to $49^{(2t - 0.5)}$

Step-by-step explanation:

Given

$49^{(2t - 0.5)}$

Required

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$49^{(2t - 0.5)}$

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Using law of indices which states;

$a^{mn} = (a^m)^n$

Applying this law to the numerator; we have

$\frac{(7^{2})^{t}}{49^{0.5}}$

Expand expression in bracket

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$\frac{49^{t}}{49^{0.5}}$ becomes

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$\frac{7^{4t}}{7^{0.5}}$

Also; Using law of indices which states;

$\frac{a^{m}}{a^n} = a^{m-n}$

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Using law of indices which states;

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