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Leokris [45]
3 years ago
13

Solve for x: 3(1 - 3x) = 2(-4x + 7)

Mathematics
1 answer:
djverab [1.8K]3 years ago
4 0

Answer:

x= -11

Step-by-step explanation:

distribute the 3 and the 2:   3 - 9x = -8x + 14

add 9x from both sides and subtract 14 from both sides:  -11 = x

x = -11

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Anil wants to multiply 5, 6, and 3. Which expression could Anil write in the box to
Elis [28]

Answer:

1) 5 * 18

Step-by-step explanation:

Because 6*3 = 18

5*6*3 = 5*18

6 0
3 years ago
Read 2 more answers
Jenna drew irregular quadrilateral ABCD inscribed in circle P. She knows that: m∠3=2⋅m∠1, and m∠2=2⋅m∠4, and m∠2+m∠3=360°. What
Mrrafil [7]

Answer:

The generalisation she can make from her work is that the other two angles of the quadrilateral are supplementary i.e their sum is 180°

Step-by-step explanation:

We are given the following from what she knows

m∠3=2⋅m∠1... 1

m∠2=2⋅m∠4 ... 2

m∠2+m∠3=360 ... 3

From what is given, we can substitute equation 1 and 2 into equation 3 as shown:

From 3:

m∠2+m∠3=360

Substituting 1 and 2 we will have:

2⋅m∠4 + 2⋅m∠1 = 360

Factor out 2 from the left hand side of the equation

2(m∠4+m∠1) = 360

Divide both sides by 2

2(m∠4+m∠1)/2 = 360/2

m∠4+m∠1 = 180°

Since the sum of two supplementary angles is 180°, hence the generalisation she can make from her work is that the other two angles of the quadrilateral are supplementary i.e their sum is 180°

7 0
3 years ago
What does x/4=3/2 equal?
MrRissso [65]
x/4 = 3/2
x/2 = 3 (multiply both sides by 2)
x = 6 (multiply both sides by 2)
Therefore 6/4 = 3/2
6 0
3 years ago
Luke started a weight-loss program. The first week, he lost X pounds. the second week he lost 3/2 pounds less then 3/2 times the
irga5000 [103]

Luke started a weight-loss program.

The first week, he lost X pounds.

the second week he lost 3/2 pounds less then 3/2 times the pounds he lost the first week. so, he lost 3/2 x - 3/2

The third week, he lost 1 more pound than 3/4 of the pounds he lost the first week. so, he lost 3/4 x + 1

So, over 3 weeks he lost :

x + (3/2 x - 3/2) + (3/4 x + 1) = 13/4 x - 1/2

=========================================================

Liam started the program when Luke did.

The first week, he lost 1 pound less than 3/2 times the pounds luke lost the first week. so, he lost (3/2 x - 1)

The second week, he lost 4 pounds less than 5/2 times the pounds luke lost the first week. so ,he lost (5/2 x - 4)

The third week, he lost 1/2 more than 5/4 times the pounds luke lost the first week. so, he lost, ( 5/4 x + 1/2)

The expression for Liam's weight loss over the three weeks is =

= (3/2 x - 1) + (5/2 x - 4) + ( 5/4 x + 1/2) = 21/4 x - 9/2

=============================================================

Assuming they both lost the same number of pounds over the three weeks

So, equating the number of pounds lost by each one of them

so,

13/4 x - 1/2 = 21/4 x - 9/2

solve for x

13/4 x - 21/4 x = -9/2 + 1/2

-2x = -4

divide both sides by -2

so,

x = -4/-2 = 2

so,

The number of pounds luke lost in the fist week is 2 pounds

=============================================================

4. The number of pounds luke and liam each lost over the three weeks is

= 13/4 * 2 - 1/2 = 6 pounds

7 0
1 year ago
Suppose a 90% confidence interval for the mean salary of college graduates in a town in Mississippi is given by [$38,737, $50,46
JulsSmile [24]

Answer:

a. The point estimate was of $44,600.

b. The sample size was of 16.

Step-by-step explanation:

Confidence interval concepts:

A confidence interval has two bounds, a lower bound and an upper bound.

A confidence interval is symmetric, which means that the point estimate used is the mid point between these two bounds, that is, the mean of the two bounds.

The margin of error is the difference between the two bounds, divided by 2.

a. What is the point estimate of the mean salary for all college graduates in this town?

Mean of the bounds, so:

(38737+50463)/2 = 44600.

The point estimate was of $44,600.

b. Determine the sample size used for the analysis.

First we need to find the margin of error, so:

M = \frac{50463-38737}{2} = 5863

Relating the margin of error with the sample size:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.9}{2} = 0.05

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a pvalue of 1 - 0.05 = 0.95, so Z = 1.64.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

For this problem, we have that \sigma = 14300, M = 5863. So

M = z\frac{\sigma}{\sqrt{n}}

5863 = 1.645\frac{14300}{\sqrt{n}}

5863\sqrt{n} = 1.645*14300

\sqrt{n} = \frac{1.645*14300}{5863}

(\sqrt{n})^2 = (\frac{1.645*14300}{5863})^2

n = 16

The sample size was of 16.

7 0
3 years ago
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