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Vika [28.1K]
3 years ago
12

What 1+1 im serious but yeah just got brainly

Mathematics
1 answer:
ad-work [718]3 years ago
3 0

Answer: 2 or 11 if trick question

Step-by-step explanation: just put 1 and 1 together

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The larger of two consecutive odd integers is four less than three times the smallest integer. Find the two integers.
ElenaW [278]

Answer: -1 and 1

Step-by-step explanation:

Let the first integer be x and the second x +2 , clearly, the larger is x + 2.

From the statement given

x + 2 = 3x + 4

x - 3x = 4 - 2

-2x = 2

x = -1

The second integer is -1 + 2 = 1

4 0
3 years ago
PLEASE HELP ME I NEED IT<br> X=<br> Y=
vampirchik [111]
X=33 and Y= 57



Step by step explanation if you see the right angle at 57 degrees it part of x so x plus 57 is 90 and 90 minus 57 is 33 so x is 33 and x and y also form a right angle so x plus y should equal 90 and 90 minus 33 is 7 so that’s Y
7 0
3 years ago
Read 2 more answers
P(t) = 2ť + 10<br> n(t) = 4<br> What’s the function (p+n) (t)?
Evgen [1.6K]

Answer:

\boxed{\sf (p + n)(t) = 2t + 14}

Given:

\sf p(t) = 2t + 10 \\ \sf n(t) = 4

To find:

\sf (f + g)(x) = f(x) + g(x)

Step-by-step explanation:

\sf \implies(f + g)x = f(x) + g(x) \\  \\ \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:    = (2t + 10) + ( 4) \\  \\ \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:    = 2t + 10 + 4 \\  \\ \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:    = 2t + 14

7 0
3 years ago
-2x-y=-9<br> 5x-2y=18<br> substitution
KIM [24]
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6 0
3 years ago
Read 2 more answers
FIND THE EQUATION OF THE LINE!!!<br>USE EXACT NUMBERS<br><br>EXAMPLE!<br><br>y= ( )x + ( ) ​
Korvikt [17]

Answer:

y=mx+b is the form to write this equation. M is the slope and B is the y intercept. therefore:

y=4x-9

Step-by-step explanation:

3 0
3 years ago
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