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babymother [125]
3 years ago
12

In what ways does adding a constant or coefficient to a quadratic equation affect the graph

Mathematics
1 answer:
lesya692 [45]3 years ago
7 0
A constant can either shift the graph up or down. If coefficient is less than 1 it will make the graph wider, if it's more than 1 it will make graph more narrow
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Show that: (3x-1)(x+5)(4x-3) = 12x^3 + 47x^2 - 62x +15 for all values of x. (3x-1)(x+5)(4x-3) = (?????)(4x-3) Expand into 6 term
lara31 [8.8K]
<span>(3x - 1)( x + 5)(4x - 3) = 12x^3 + 47x^2 - 62x +15 </span>
<span>(3x^2 – x + 15x - 5)( 4x – 3 ) = <span>12x^3 + 47x^2 - 62x +15 </span></span>
<span>(3x^2 + 14x - 5)( 4x – 3 ) = <span>12x^3 + 47x^2 - 62x +15 </span></span>
<span>12x^3 – 9x^2 + 56x^2 – 42x – 20x + 15 = <span>12x^3 + 47x^2 - 62x +15 </span></span>
<span>12x^3 – 47x^2 - 62x + 15 = <span>12x^3 + 47x^2 - 62x +15 </span></span>

<span> </span>

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3 years ago
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bogdanovich [222]
{-1, 5, 11, 17, 23} ................
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3 years ago
Greatest 3 digit multiple of 33 using 3 diffrent digits
mel-nik [20]

Answer:

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Masteriza [31]

Hey there!

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2. 5s-10 This can be found by distributing the first equation, multiplying both s and -2 by 5.

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4. 5(s) + 5(-2) This one is most like the first one, except it's a little more spread out. Multiply the term s by the 5 sides in one grouping, and the integer -2 by 5 in the other.

Hope this helps!

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Show your work<br><br>Show your work to back up your answer
attashe74 [19]
So it’s $15 per month so that is what you are gonna multiply by x. You start out with $75 so that’s the initial fee. 15x + 75 is your expression.
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