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kramer
3 years ago
7

PLEASE HELP IT IS ALMOST DUE !!

Mathematics
1 answer:
zhenek [66]3 years ago
3 0

Answer:

it is a function

Step-by-step explanation:

Because on the X-axis there is no numbers repeating making it a function

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Original price; 30.50; Markdown 30%
Stels [109]

Answer:

After the markdown, the cost will be $21.35

Step-by-step explanation:

This is shown by multiplying the original price, 30.50 by 30%, or 0.30 to get 9.15. Next you subject your product from the original price to get the marked down value at 21.35.

8 0
4 years ago
You are rolling two dice at the same time. What is the probability of rolling a sum of 5 or 9?
baherus [9]
You can get a 5 by rolling :
1 and 4
2 and 3
3 and 2
4 and 1

You can get a 9 by rolling :
3 and 6
4 and 5
5 and 4
6 and 3

There are 36 possible outcomes, hence your probability is \frac{4\cdot2}{36}=\boxed{\frac29}
8 0
3 years ago
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Please help me asap!!!!!!!!
lesantik [10]
12.) This does not follow the rule of conservation because on the reactant side there is one Na and two Cl while the product side only has one Na and Cl. They are not equal and do not have the same number of atoms for the different elements. In the law of conservation matter cannot be created or destroyed and this does not follow the law.

13.) 2Na + Cl2 —> 2NaCl

Put a 2 in front of Na and a 2 in front of NaCl
4 0
3 years ago
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Consider the following division of polynomials.
Bond [772]

x^4=x^2\cdot x^2. Multiplying the denominator by x^2 gives

x^2(x^2+2x+8)=x^4+2x^3+8x^2

Subtracting this from the numerator gives a remainder of

(x^4+x^3+7x^2-6x+8)-(x^4+2x^3+8x^2)=-x^3-x^2-6x+8

-x^3=-x\cdot x^2. Multiplying the denominator by -x gives

-x(x^2+2x+8)=-x^3-2x^2-8x

and subtracting this from the previous remainder gives a new remainder of

(-x^3-x^2-6x+8)-(-x^3-2x^2-8x)=x^2+2x+8

This last remainder is exactly the same as the denominator, so x^2+2x+8 divides through it exactly and leaves us with 1.

What we showed here is that

\dfrac{x^4+x^3+7x^2-6x+8}{x^2+2x+8}=x^2-\dfrac{x^3+x^2+6x-8}{x^2+2x+8}

=x^2-x+\dfrac{x^2+2x+8}{x^2+2x+8}

=x^2-x+1

and this last expression is the quotient.

To verify this solution, we can simply multiply this by the original denominator:

(x^2+2x+8)(x^2-x+1)=x^2(x^2-x+1)+2x(x^2-x+1)+8(x^2-x+1)

=(x^4-x^3+x^2)+(2x^3-2x^2+2x)+(8x^2-8x+8)

=x^4+x^3+7x^2-6x+8

which matches the original numerator.

3 0
3 years ago
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Berry waked the dog for 20 minutes.
Sergeu [11.5K]
Chris walked the dog for 80 minutes or 1 hour and 20 minutes
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