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svetoff [14.1K]
3 years ago
5

Solve 5/7x=-25 The solution is x= ?

Mathematics
1 answer:
Bad White [126]3 years ago
4 0
The answer To this is x=-35
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Danielle wants to buy a magazine for $11. The sales tax is 5%. How much would the total cost of the magazine be with tax include
dimulka [17.4K]

Answer:

$11.55

Step-by-step explanation:

If we convert the percentage to 1.05 and multiply it by 11, it's 11.55.

7 0
3 years ago
How many times greater is the area of circle C than the area of circle A.
kicyunya [14]

Answer:

I need a picture

Step-by-step explanation:

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5 0
3 years ago
Y^2– 14y + 48 = 0<br> Solve the following quadratic equations by completing the square.
Troyanec [42]
Step by step:
y^2- 14y+48=0
y^2-14y=-48
y^2-14y+49=-48+49
(y-7)^2=1

Answer: y=7+-1
4 0
3 years ago
I NEED THIS ASAP RN PLEASE
artcher [175]

Answer:

5:2

Step-by-step explanation:

Start with what the question is asking for, which is the ratio of math problems to minutes.

With ratios "to" also means ":", so you can change it to math problems : minutes.

Then, substitute the numbers for the labels. Math problems = 10 and minutes = 4, so now you have 10:4

Lastly, to simplify the ratio, find the greatest common factor, in this case 2, and divide both sides, which gives you your answer 5:2

4 0
3 years ago
Read 2 more answers
Write the equation of a polynomial of degree 3, with zeros 1, 2 and -1 where f(0)=2
drek231 [11]

<u>Answer:</u>

The equation of a polynomial of degree 3, with zeros 1, 2 and -1 is x^{3}-2 x^{2}-x+2=0

<u>Solution:</u>

Given, the polynomial has degree 3 and roots as 1, 2, and -1. And f(0) = 2.

We have to find the equation of the above polynomial.

We know that, general equation of 3rd degree polynomial is  

F(x)=x^{3}-(a+b+c) x^{2}+(a b+b c+a c) x-a b c=0

where a, b, c are roots of the polynomial.

Here in our problem, a = 1, b = 2, c = -1.

Substitute the above values in f(x)

F(x)=x^{3}-(1+2+(-1)) x^{2}+(1 \times 2+2(-1)+1(-1)) x-1 \times 2 \times(-1)=0

\begin{array}{l}{\rightarrow x^{3}-(3-1) x^{2}+(2-2-1) x-(-2)=0} \\ {\rightarrow x^{3}-(2) x^{2}+(-1) x-(-2)=0} \\ {\rightarrow x^{3}-2 x^{2}-x+2=0}\end{array}

So, the equation is x^{3}-2 x^{2}-x+2=0

Let us put x = 0 in f(x) to check whether our answer is correct or not.

\mathrm{F}(0) \rightarrow 0^{3}-2(0)^{2}-0+2=2

Hence, the equation of the polynomial is x^{3}-2 x^{2}-x+2=0

3 0
3 years ago
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