3 years ago

Y^2– 14y + 48 = 0 Solve the following quadratic equations by completing the square.

Mathematics

1 answer:

Troyanec [42]3 years ago

4 0

Step by step:
y^2- 14y+48=0
y^2-14y=-48
y^2-14y+49=-48+49
(y-7)^2=1

Answer: y=7+-1

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