In the figure above, what is the area of triangle QRS?
1 answer:
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Answer:
Low Q1 Median Q3 High
6 9 11 12.5 14
The interquartile range = 3.5
Step-by-step explanation:
Given that:
Consider the following ordered data. 6 9 9 10 11 11 12 13 14
From the above dataset, the highest value = 14 and the lowest value = 6
The median is the middle number = 11
For Q1, i.e the median of the lower half
we have the ordered data = 6, 9, 9, 10
here , we have to values as the middle number , n order to determine the median, the mean will be the mean average of the two middle numbers.
i.e
median =
median =
median = 9
Q3, i.e median of the upper half
we have the ordered data = 11 12 13 14
The same use case is applicable here.
Median =
Median =
Median = 12.5
Low Q1 Median Q3 High
6 9 11 12.5 14
The interquartile range = Q3 - Q1
The interquartile range = 12.5 - 9
The interquartile range = 3.5
Answer:
C. x³+10x²−5x+5
E. 7x⁵+4x²
F. x+8
Step-by-step explanation:
The graph they described should look something like the one i drew below.
So all you have to do is look at the number with the highest exponent.
If the exponent is an odd number and the x is positive then that function will have an end behavior like the picture i posted.
x³ is good
-x³ is bad because of the negative sign
x² is bad because exponent is even
x⁷ is good
123x¹ is good
