Question

Write a quadratic function in standard form with axis of symmetry x=-5 and y -intercept 3 .

Answer 1

Answer:

follow the statement below

Step-by-step explanation:

The question you presented here has multiple (un-limited) solutions unless you have another condition to solve for a single solution.

Equation: y = ax² + bx + c

y intercept (0 , 3): c = 3

axis of symmetry x=-5, therefore a corresponding point (-10,3) on the curve

3 = a*(-10)² + b*(-10) + 3

100a - 10b = 0

b = 10a  .... any pair like a=0.5 b=5; a=1 b=10 0r a=2 b=20 ..... all fit the function

y = 0.5x² + 5x +3

y = x² + 10x + 3

y = 2x² + 20x +3

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