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3 years ago

PLEASE HELP ME!!!!!!!!!!!!!!!!!!!!!11

1 answer:

6 0

The first thing to do in this case is to replace the value of x = 60 in the given function to obtain the average fuel mileage in miles per gallon.
We then have to replace:
y = -0.0088 * x ^ 2 + 0.79 * x + 15
y = -0.0088 * (60) ^ 2 + 0.79 * (60) + 15
y = 30.7 mi / gal
answer
the best approximate for the average gas mileage at a speed of 60 miles per hour is
B) 30.7 mi / gal

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Norma-Jean [14]

I really do not get it . It’s this a question ? If so can you be a little more specific .

4 0

2 years ago

What is the solution to log 5 (x+30)= 3

Free_Kalibri [48]

Answer:

x = 95

Step-by-step explanation:

Using the rule of logarithms

• $log_{b}$ x = n ⇔ x = $b^{n}$

Given

$log_{5}$ (x + 30) = 3, then

x + 30 = 5³ = 125 ( subtract 30 from both sides )

x = 95

7 0

3 years ago

PLEASE HELP!!!:)). The area of the trampezoid is 100dm and the bases are 2.1m and 1.9m. Calculate the height of the trampezoid

mixas84 [53]

Answer:

Well, the only thing you should do is to use the formula.

if the bases are: a, b

and the height is=h

Then, this is your formula, S=½(a+b)×h

Step-by-step explanation:

Aight,

100dm=10m

S=10m

now, the formula

10=½(2.1+1.9)×h===> 20=4h==> h=5m

5 0

2 years ago

At a gas station, it takes 14 seconds to pump 2 gallons of gas. if the amount of gasoline pumped varies directly with time, how

EleoNora [17]

Answer:

See below:

Step-by-step explanation:

If we do this, we know that 2 gallons takes 14 seconds. (2:14)

Based on that data, we can know that 1 gallon takes 7 seconds. (1:7)

-> 2/14 = 1/7

Now we can multiply by 12 to get 12 gallons on one side.

What we do on one side has to happen to the other side.

So, 12 gallons * 1 gallons = 12 gallons and 12 gallons * 7 gallons = 84 gallons.

So the final answer is 85 gallons,

7 0

2 years ago

Read 2 more answers

To find the product of a 2 digit number and 1 digit number, you can multiply the tens, multiply the ones, and find the sum of ea

NARA [144]

Of each ones place.... Or ... The sum of each number? Just trying to help.....

8 0

2 years ago