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2 years ago

Given that x = 5.4 m and 0 = 26°, work out BC rounded to 3 SF.

Mathematics

1 answer:

bagirrra123 [75]2 years ago

4 0

Answer:

BC ≈ 4.85 m

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos26° = $\frac{adjacent}{hypotenuse}$ = $\frac{BC}{AC}$ = $\frac{BC}{5.4}$ ( cross- multiply )

5.4 × cos26° = BC , then

BC ≈ 4.85 m ( to 3 s f )

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Mrac [35]

If angle TSV=6x+17 then arc it intercept (SV)would be double it

6x+17=1/2 (15x+13)
12x+34=15x+13
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Arc SV=15(7)+13
=118

And angle TSV=6(7)+17
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There are 360 degrees in a circle and the measure of the arc would be equal to the central point so the sum of all the arcs equals 360

Arc SV+ arc SUV=360
118+SUV=360
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2 years ago

Airline companies are interested in the consistency of the number of babies on each flight, so that they have adequate safety eq

Ilia_Sergeevich [38]

Answer:

-Conducting the survey on a holiday weekend will not produce representative results

-The survey was conducted using six similar flights

-The survey would not be a true representation of the entire population of air travelers

Step-by-step explanation:

First of all, the sampling method that was used in this survey/study was a convenience sampling, were they just used the data that was readily available, which in this case were the 6 flights from Boston to Salt Lake City.

This sampling method is useful for pilot studies and for identifying tendencies, however, the obtained sample is not representative of the population, and because there is no criteria to organize the sample, (for example there was no fight with a different route taking into account) it is impossible to obtain statistical results that are precise.

And besides that, the fact that the survey was carried out over Thanksgiving weekend is also a factor that can directly affect the results, so it needs to be taken into account as a variable, which in this study was not.

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3 years ago

Find the missing side of each triangle. Round your answers to the nearest tenth if necessary. (Please Show your work)

svlad2 [7]

<h2>>> Answer </h2>

___________

$\:$

$\boxed{ \rm{answer \: by \: { \boxed{ \rm{☆HayabusaBrainly}}}}}$

Step by step :

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2 years ago

Use Cramer’s rule to solve for x: x + 4y − z = −14 5x + 6y + 3z = 4 −2x + 7y + 2z = −17

V125BC [204]

Looks like the system is

x + 4y - z = -14

5x + 6y + 3z = 4

-2x + 7y + 2z = -17

or in matrix form,

$\mathbf{Ax} = \mathbf b \iff \begin{bmatrix} 1 & 4 & -1 \\ 5 & 6 & 3 \\ -2 & 7 & 2 \end{bmatrix} \begin{bmatrix} x \\ y \\ z \end{bmatrix} = \begin{bmatrix} -14 \\ 4 \\ -17 \end{bmatrix}$

Cramer's rule says that

$x_i = \dfrac{\det \mathbf A_i}{\det \mathbf A}$

where $x_i$ is the solution for i-th variable, and $\mathbf A_i$ is a modified version of $\mathbf A$ with its i-th column replaced by $\mathbf b$ .

We have 4 determinants to compute. I'll show the work for det(A) using a cofactor expansion along the first row.

$\det \mathbf A = \begin{vmatrix} 1 & 4 & -1 \\ 5 & 6 & 3 \\ -2 & 7 & 2 \end{vmatrix}$

$\det \mathbf A = \begin{vmatrix} 6 & 3 \\ 7 & 2 \end{vmatrix} - 4 \begin{vmatrix} 5 & 3 \\ -2 & 2 \end{vmatrix} - \begin{vmatrix} 5 & 6 \\ -2 & 7 \end{vmatrix}$

$\det \mathbf A = ((6\times2)-(3\times7)) - 4((5\times2)-(3\times(-2)) - ((5\times7)-(6\times(-2)))$

$\det\mathbf A = 12 - 21 - 40 - 24 - 35 - 12 = -120$

The modified matrices and their determinants are

$\mathbf A_1 = \begin{bmatrix} -14 & 4 & -1 \\ 4 & 6 & 3 \\ -17 & 7 & 2\end{bmatrix} \implies \det\mathbf A_1 = -240$

$\mathbf A_2 = \begin{bmatrix} 1 & -14 & -1 \\ 5 & 4 & 3 \\ -2 & -17 & 2 \end{bmatrix} \implies \det\mathbf A_2 = 360$

$\mathbf A_3 = \begin{bmatrix} 1 & 4 & -14 \\ 5 & 6 & 4 \\ -2 & 7 & -17 \end{bmatrix} \implies \det\mathbf A_3 = -480$

Then by Cramer's rule, the solution to the system is

$x = \dfrac{-240}{-120} \implies \boxed{x = 2}$

$y = \dfrac{360}{-120} \implies \boxed{y = -3}$

$z = \dfrac{-480}{-120} \implies \boxed{z = 4}$

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1 year ago

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Aleksandr [31]

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Hope this helps

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2 years ago