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Svetradugi [14.3K]

4 years ago

9

I need help on figuring this one out !

2 answers:

vladimir2022 [97]4 years ago

7 0

Answer:

5.851

7.6072

7.67

7.7

Step-by-step explanation:

Just choose the lowest decimal numbers and the lowest whole number and that is the smallest number

I hope this helps you :]

nignag [31]4 years ago

6 0

Answer:

5.851, 7.6072, 7.67, 7.7

Step-by-step explanation:

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Richard's annual take-home pay is 28500. What is the maximum amount that he can spend per month paying off credit cards and loan

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To answer the problem above, annual means yearly, to know the maximum amount that he can spend per month we simply divide the annual take-home pay with 12 months exactly. So 28500 / 12 = 2375. Richard can spend not more than 2375 to not be in danger of credit overload.

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3 years ago

A lie detector is known to be 4/5 reliable when the person is guilty and 9/10 reliable when the person is innocent. If a suspect

shtirl [24]

Answer:

0.0748 = 7.48% probability that he is guilty

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Tests indicates guilty

Event B: Person is guilty

Probability that the test indicates that the person is guilty:

4/5 = 0.8 of 1/100 = 0.01(person is guilty)

1 - 0.9 = 0.1 of 1 - 0.99(person is not guilty). So

$P(A) = 0.8*0.01 + 0.1*0.99 = 0.107$

Test indicates guilty and the person is guilty;

0.01 of 0.8. So

$P(A \cap B) = 0.01*0.8 = 0.008$

What is the probability that he is guilty?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.008}{0.107} = 0.0748$

0.0748 = 7.48% probability that he is guilty

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4 years ago

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As the question points out, the equation is indeed separable:

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{6x+9}{12y^2+16y+6}$

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Integrate both sides to get

$2(2y^3+4y^2+3y)=3(x^2+3x)+C$

$\implies F(x,y)=\underbrace{(-3x^2-9x)}_{G(x)}+\underbrace{4y^3+8y^2+6y}_{H(y)}=C$

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