The problem is asking how much each person will need to pay. Simplifying the problem into an equation with variables (an algorithm) will greatly help you solve it:
S = Sales Tax = $ 7.18 per any purchase
A = Admission Ticket = $ 22.50 entry price for one person (no tax applied)
F = Food = $ 35.50 purchases for two people
We know the cost for one person was: (22.50) + [(35.50/2) + 7.18] =
$ 47.43 per person. Now we can check each method and see which one is the correct algorithm:
Method A)
[2A + (F + 2S)] / 2 = [ (2)(22.50) + [35.50 + (2)(7.18)] ]/ 2 = $47.43
Method A is the correct answer
Method B)
[(2A + (1/2)F + 2S) /2 = [(2)(22.50) + 35.50(1/2) + (2)7.18] / 2 = $38.55
Wrong answer. This method is incorrect because the tax for both tickets bought are not being used in the equation.
Method C)
[(A + F) / 2 ]+ S = [(22.50 + 35.50) / 2 ] + 7.18 = $35.93
Wrong answer. Incorrect Method. The food cost is being reduced to the cost of one person but admission price is set for two people.
Answer:
Step-by-step explanation:
GIVEN: A bag contain 
red marbles,
green marbles and 
blue marble. A marble is chosen at random from the bag and not replaced, then a second marble is chose.
TO FIND: What is the probability both marbles are green.
SOLUTION:
Total marbles in bag 
total number of green marbles 
Probability that first marble will be green 
Probability that second marble will be green 
As both events are disjoint
probability both marbles are green 
Hence the probability both marbles are green is
Answer:
CHEEEESEEE
Step-by-step explanation:
CHEESEBURGER CHEESECAKE GRILLED CHEESE CHEESESTICKS CHEEESE ENCHILIADAS BROCOLLI CHEESE SOUP CREAMY MAC AND CHEESE POTATO CHEESE BALLS hAM & CHEESE SANDWICH CHEESE EVERYTHING MUAHAHHAHAAHAHAHAAAAAAAAAAAAAAAAAAAAAAAA
Answer:
3x^2y^2
Step-by-step explanation:
I think:
3*2*x*x*x*y*y*y*y
3*3*x*x*y*y
3*6*x*x*x*y*y
They all have 3x^2y^2 in common.
