Question

What is the solution set of x^2+y^2=26 and x-y=6

Answer 1

Solution is in the picure

Good luck :)

Answer 2

$x^{2} + y^{2} =26 x-y=6 x=y+6 Replacing in equation; (y+6[tex] )^{2}$+$y^{2}$=26
$y^{2} +12x+36+ y^{2} =36$
=$2y^{2} +12x+36-26=0$
=$2y^{2} +12x+10=0$
Product = 12
Sum= 10
factoring;
2$y^{2}$+2y+10y+10=0
2y(y+1)+10(y+1)=0
(2y+10)(y+1)=0
y=-1 or 2y=-10
y=-5
x=y+6
When y =-1
x=-1+6
x=5
when y =-5
x=-5+6
x=+1