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Zina [86]
3 years ago
6

You have to answer 2 questions for the exam. There are 7 essays to choose from. How many different groups of 2 essays could you

possibly choose?
Mathematics
1 answer:
Alex777 [14]3 years ago
6 0

Answer:

21

Step-by-step explanation:

Since the order of the essays isn't important, the number of ways you can choose 2 from 7 is:

₇C₂ = 7! / (2! (7−2)!)

₇C₂ = 7! / (2! 5!)

₇C₂ = 7×6×5! / (2×1 × 5!)

₇C₂ = 7×6 / 2

₇C₂ = 21

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Answer:

b = 25m

Step-by-step explanation:

Hi there!

We're given angle B and the length of <em>a</em> in this right triangle. We must solve for the length of <em>b</em>. <em>a</em> and <em>b</em> are the two legs of the right triangle.

In this case, we can use the tangent ratio:

tan\theta=\displaystyle\frac{opposite}{adjacent}

Plug in the given information:

tan\displaystyle\frac{\pi}{4} =\displaystyle\frac{b}{25}\\\\25tan\displaystyle\frac{\pi}{4} =b\\\\b=25

Therefore, b = 25m.

We can also use this using special triangle rules. \displaystyle\frac{\pi}{4} radians is equal to 45 degrees, making this a 45-90-45 triangle. This would make <em>a</em> and <em>b</em> equal in length.

I hope this helps!

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Step-by-step explanation:

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Step-by-step explanation:

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