The final step in the object-oriented design (OOD) process consists of developing the <u>package diagrams.</u>
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In the field of Computer studies, object-oriented design (OOD) can be described as a design method in which a proper system of interacting objects is planned for making a computing system or software.
The final step of an object-oriented design (OOD) involves the development of package diagrams. Package diagrams are structures or diagrams that are used for representing the model elements. The model elements are shown as packages in this kind of diagram.
Package diagrams are the final step of an object-oriented design process because they help to provide a visual idea of the overall proposed design.
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1.)
<span>((i <= n) && (a[i] == 0)) || (((i >= n) && (a[i-1] == 0))) </span>
<span>The expression will be true IF the first part is true, or if the first part is false and the second part is true. This is because || uses "short circuit" evaluation. If the first term is true, then the second term is *never even evaluated*. </span>
<span>For || the expression is true if *either* part is true, and for && the expression is true only if *both* parts are true. </span>
<span>a.) (i <= n) || (i >= n) </span>
<span>This means that either, or both, of these terms is true. This isn't sufficient to make the original term true. </span>
<span>b.) (a[i] == 0) && (a[i-1] == 0) </span>
<span>This means that both of these terms are true. We substitute. </span>
<span>((i <= n) && true) || (((i >= n) && true)) </span>
<span>Remember that && is true only if both parts are true. So if you have x && true, then the truth depends entirely on x. Thus x && true is the same as just x. The above predicate reduces to: </span>
<span>(i <= n) || (i >= n) </span>
<span>This is clearly always true. </span>
Answer:
A. weekrep101
Explanation:
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This is the answer hope it helps :D
The correct answer is Boolean logic.
Booleans are true or false statements.
An example of a while loop is:
while 1 < 5:
#do something.
The Boolean statement is 1 < 5 which evaluates to true because 1 is less than 5.
I hope this helps!