All categories

3 years ago

HELP PLZ ALMOST DONE!!!

Mathematics

2 answers:

lora16 [44]3 years ago

8 0

Answer:

A = 30 inches^2

Step-by-step explanation:

The area of a trapezoid is given by

A = 1/2 (b1+b2)h where b1 and b2 are the lengths of the bases

A = 1/2 ( 10+5) * 4

A = 1/2 (15)*4

A = 30 inches^2

Yanka [14]3 years ago

6 0

Answer:

Area of trapezoid is 30 inches ².

Step-by-step explanation:

<h3><u>Question</u> :-</h3>

A trapezoid having length of Base ¹ and Base ² are 10 in. and 5 in. and it's height is 4 in. Find the area of trapezoid.

<h3><u>Solution</u> :-</h3>

Area of trapezoid is given by

= 1/2 × ( B¹ + B² ) × h

Where, B¹ = 10 in.

B ² = 5 in.

h = 4 in.

substitute the values

Area = 1 / 2 × ( 10 in × 5 in ) × 4 in

multiplying the values

Area = 1 / 2 × 15 in. × 4 in

Area = 1 / 2 × 60 in ².

Area = 30 in².

Hence, Area of trapezoid is 30 inches ².

You might be interested in

Write two different expressions equivalent to 8d-4

Vedmedyk [2.9K]

Answer:

2(4d-2) & 4(2d-1)

Step-by-step explanation:

I cant explain but,

Hope this answer Help!!!!

Have A Nice Day/Night!!!!!

5 0

3 years ago

Read 2 more answers

Need help with this please.

sp2606 [1]

Answer:

$y = -\frac{3}{2} x + 4$

Step-by-step explanation:

First, let us find the gradient of AB:

Gradient of AB = $\frac{-1-3}{-1-5}$

= $\frac{2}{3}$

We also need to know that The <em>product of gradients which are perpendicular to each other is -1</em>. Using this idea, we can find the gradient of the perpendicular bisector:

(Gradient of perpendicular bisector)( $\frac{2}{3}$ ) = -1

Gradient of perpendicular bisector = $-\frac{3}{2}$

Now, we need to know at which coordinates the perpendicular bisector intersects AB. <em>A perpendicular bisector bisects a line to two equal parts</em>. Hence the <em>coordinates of the intersection point is the midpoint of AB</em>. Thus,

Coordinates of intersection = ( $\frac{-1 + 5}{2}$ , $\frac{-1 + 3}{2}$ )

= ( 2, 1 )

Now, we can construct our equation. The equation of a line can be formed using the formula $(y - y_{1}) = m(x - x_{1})$ where $m$ is the gradient and the line passes through $(x_{1} , y_{1} )$ . Hence by substituting the values, we get: