Let's solve your equation step-by-step.<span><span><span>0.2<span>(<span>x+50</span>)</span></span>−6</span>=<span>0.4<span>(<span><span>3x</span>+20</span>)</span></span></span>Step 1: Simplify both sides of the equation.<span><span><span>0.2<span>(<span>x+50</span>)</span></span>−6</span>=<span>0.4<span>(<span><span>3x</span>+20</span>)</span></span></span><span><span><span><span><span><span>(0.2)</span><span>(x)</span></span>+<span><span>(0.2)</span><span>(50)</span></span></span>+</span>−6</span>=<span><span><span>(0.4)</span><span>(<span>3x</span>)</span></span>+<span><span>(0.4)</span><span>(20)</span></span></span></span>(Distribute)<span><span><span><span><span>0.2x</span>+10</span>+</span>−6</span>=<span><span>1.2x</span>+8</span></span><span><span><span>(<span>0.2x</span>)</span>+<span>(<span>10+<span>−6</span></span>)</span></span>=<span><span>1.2x</span>+8</span></span>(Combine Like Terms)<span><span><span>0.2x</span>+4</span>=<span><span>1.2x</span>+8</span></span><span><span><span>0.2x</span>+4</span>=<span><span>1.2x</span>+8</span></span>Step 2: Subtract 1.2x from both sides.<span><span><span><span>0.2x</span>+4</span>−<span>1.2x</span></span>=<span><span><span>1.2x</span>+8</span>−<span>1.2x</span></span></span><span><span><span>−<span>1x</span></span>+4</span>=8</span>Step 3: Subtract 4 from both sides.<span><span><span><span>−<span>1x</span></span>+4</span>−4</span>=<span>8−4</span></span><span><span>−<span>1x</span></span>=4</span>Step 4: Divide both sides by -1.<span><span><span>−<span>1x</span></span><span>−1</span></span>=<span>4<span>−1</span></span></span><span>x=<span>−4</span></span>Answer:<span>x=<span>−<span>4</span></span></span>
2(7/2)^x = 49/2
Divide both sides by 2:
(7/2)^x = 49/4
I notice that 49/4 can be rewritten as (7/2)^2, so we now have:
(7/2)^x = (7/2)^2
The only way for this to be true is if x = 2. Thus, we are done.
Answer:
For this case we want to check if the true mean for the depth of groves cut into aluminium by a machine is equal to 1.7 (null hypothesis) and the alternative hypothesis would be the complement different from 1.7. And the best system of hypothesis are:
Null hypothesis: 
Alternative hypothesis ![\mu \neq 1.7[/tx]And the best system of hypothesis are:3. This two-sided test: H0: μ = 1.7 mm H1: μ ≠ 1.7 mmStep-by-step explanation:For this case we want to check if the true mean for the depth of groves cut into aluminium by a machine is equal to 1.7 (null hypothesis) and the alternative hypothesis would be the complement different from 1.7. And the best system of hypothesis are:Null hypothesis: [tex]\mu =1.7](https://tex.z-dn.net/?f=%5Cmu%20%5Cneq%201.7%5B%2Ftx%5D%3C%2Fp%3E%3Cp%3EAnd%20the%20best%20system%20of%20hypothesis%20are%3A%3C%2Fp%3E%3Cp%3E3.%20This%20two-sided%20test%3A%0A%3C%2Fp%3E%3Cp%3EH0%3A%20%CE%BC%20%3D%201.7%20mm%0A%3C%2Fp%3E%3Cp%3EH1%3A%20%CE%BC%20%E2%89%A0%201.7%20mm%3C%2Fp%3E%3Cp%3E%3Cstrong%3EStep-by-step%20explanation%3A%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3EFor%20this%20case%20we%20want%20to%20check%20if%20the%20true%20mean%20for%20the%20depth%20of%20groves%20cut%20into%20aluminium%20by%20a%20machine%20is%20equal%20to%201.7%20%28null%20hypothesis%29%20and%20the%20alternative%20hypothesis%20would%20be%20the%20complement%20different%20from%201.7.%20And%20the%20best%20system%20of%20hypothesis%20are%3A%3C%2Fp%3E%3Cp%3ENull%20hypothesis%3A%20%5Btex%5D%5Cmu%20%3D1.7)
Alternative hypothesis [tex]\mu \neq 1.7[/tx]
And the best system of hypothesis are:
3. This two-sided test:
H0: μ = 1.7 mm
H1: μ ≠ 1.7 mm
In 5xy it would be 5x×1y and then 2y if they variable doesn't have a number infront of it it is assumed to be a One.
I did it on the calculator the answer was 0.1833333333333333 i do not know if this is correct if its incorrect then srry :(