The numbers are 105 and 50
<em><u>Solution:</u></em>
Let "x" be the first number
Let "y' be the second number
Twice a number plus twice a second number is 310
Therefore,
twice of x + twice of y = 310
2x + 2y = 310 ---------- eqn 1
The difference between the numbers is 55
x - y = 55 -------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
From eqn 2,
x = 55 + y ------ eqn 3
<em><u>Substitute eqn 3 in eqn 1</u></em>
2(55 + y) + 2y = 310
110 + 2y + 2y = 310
4y = 310 - 110
4y = 200
<h3>y = 50</h3>
<em><u>Substitute y = 50 in eqn 3</u></em>
x = 55 + 50
<h3>x = 105</h3>
Thus the numbers are 105 and 50
Answer:
$418
Step-by-step explanation:
So first we need to find how much a single ticket will cost.
Subtract the service fee to get how much it cost for 8 tickets.
229-13=216
Then divide that number by 8 to find how much a single ticket costs.
216÷8=27
1 ticket costs $27.
Multiply that by 15 to get how much 15 tickets cost.
27×15=405
Then add back the service fee.
405+13=418
Answer: 2 Squared is the answer
Step-by-step explanation:
Squared with 8 and 6 imagine 6 parcel and 8 sides.
It minus's to equal the equation 2.
Answer:
42
Step-by-step explanation:
8+8+12+4+4+3+3
Something like this for the problem.
Answer:
-14
Step-by-step explanation:
subtract
