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aivan3 [116]
3 years ago
11

The expressions given represent the measures of the acute angles of a right triangle Find the measure of each acute angle.

Mathematics
1 answer:
olasank [31]3 years ago
4 0

Answer:

30, 60

Step-by-step explanation:

The sum of a triangles angles should be 180.

Subtract 90 because it's a right triangle.

180 - 90 = 90

Now we know the sum of the other angles should be 90.

x + 2x = 90

Solve for x.

3x = 90

x = 30

Now you substitute 30 for x.

(30), 2(30)

30, 60

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Solve the following equation show your work 3{-x + (2x + 1)} = x - 1
Reika [66]

Answer:

x = -2

Step-by-step explanation:

For this problem, we must simply solve for x.  To do this, we will need equation operations, and the use of the distributive property.

Let's work this line by line until we have the value for x:

3{-x + (2x + 1)} = x - 1

3*-x + 3*(2x + 1) = x - 1

-3x + 6x + 3 = x - 1

3x + 3 = x - 1

2x = -4

x = -2

Now we can check our answer for x by plugging back into the original equation and see if the left hand side is equal to the right hand side:

3{-x + (2x + 1)} = x - 1

3{-(-2) + (2(-2) + 1)} ?= (-2) - 1

3{2 + (-4 + 1)} ?= -3

3{2 + (-3)} ?= -3

3{-1} ?= -3

-3 == -3

Thus, we have found the solution for x to be equivalent to negative 2.

Cheers.

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3 years ago
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Sergio [31]

Step-by-step explanation:

The answer is option b.

Explanation in the pic.

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4 years ago
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nikitadnepr [17]

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Using the completing-the-square method, rewrite f(x) = x2 - 6x + 2 in vertex form.<br>​
sp2606 [1]

Answer:

\large\boxed{f(x)+(x-3)^2-7}

Step-by-step explanation:

\text{The vertex form of equation}\ y=ax^2+bx+c:\\\\y=a(x-h)^2+k\\\\\text{We have the equation:}\\\\f(x)=x^2-6x+2=x^2-2(x)(3)+1=x^2-2(x)(3)+3^2-3^2+2\\\\\text{Use}\ (a-b)^2=a^2-2ab+b^2\to x^2-2(x)(3)+3^2=(x-3)^2\\\\f(x)=(x-3)^2-9+2=(x-3)^2-7

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3 years ago
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fenix001 [56]

Answer: 0.051

Step-by-step explanation: Am very big brain, My IQ is above your comprehension.

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