Answer:
Step-by-step explanation:
Given that:
To bet $5 that the outcome is any one of these five possibilities: 0, 00, 1, 2, 3.
Let Y represent the Amount of net profit
Then, Y= {-5, 30}
The probability distribution of Y is:
Y -5 30
P(Y=y)

a) The expected value of X is given by:
![E[Y] =\sum y P(Y=y)= 30*\dfrac{5}{38}-5*\dfrac{33}{38}](https://tex.z-dn.net/?f=E%5BY%5D%20%3D%5Csum%20y%20P%28Y%3Dy%29%3D%2030%2A%5Cdfrac%7B5%7D%7B38%7D-5%2A%5Cdfrac%7B33%7D%7B38%7D)


b)
On a bet of $5 on the number 25 we are expected to loose 24 cents.
While on a $5 bet that the outcome is any one of the numbers 0,00, or 1 we are expected to loose 39 cents.
Hence, $5 bet on the number 27 is better. Because the expected loss is less in this bet
An equation with a difference of 6 would be 12-6=6
Answer:
Step-by-step explanation:
For a number to be divisible by 4 you just need to worry about the 10s and 1s place. You also want to know that the 1s cylce every 20, or in other words:
4 8 12 16 20
24 28 32 36 40 and so on. So the only numbers that x can be there are 1, 3, 5, 7, 9. Does that make sense? and can you manage the rest?
Answer:
4
Step-by-step explanation:
pythagoras theorem = a* + b* = c* ( by '*' i mean squared)
2* + b* = square root twenty
4 + b* = 20
b* = 16
b = 4
Answer:
2
2
−
4
Step-by-step explanation: