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Xelga [282]
3 years ago
8

URGENT PLEASE HELP: 1 - 2 cos^2r = - sin^2r - 1 True False

Mathematics
1 answer:
OleMash [197]3 years ago
8 0

Answer:

false

Step-by-step explanation:

1-2cos²r=1-2(1-sin²r)=1-2+2sin²r=2sin²r-1

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a team of scientists estimate the current number of butterflies In A park to be 20 thousand. the butterfly population is expecte
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 Current number of butterflies in the park = 20 thousand.


 Rate of increase of butterfly population = 4% = 0.04


The population of butterfly after 1 year = 20+0.04*20 = 20*1.04


The population of butterfly after 2 years =  20*1.04 + 20*1.04*0.04 = 20*1.04*1.04


 The population of butterfly after 3 years =  20*1.04*1.04 + 20*1.04*1.04*0.04 = 20*1.04*1.04*1.04


So, population of butterfly after n years = 20*(1.04*1.04*1.04* .... n times)


                                                                 



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What is 8.05 × 10-5 in standard notation?
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Answer:0.0000805

Step-by-step explanation:

Edgenuity says it’s right

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3 years ago
4. A man bought a clock for $6 000 and sold it to make a profit of 15%. What was his
alukav5142 [94]

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Step-by-step explanation:

he sold it for 900 dollars

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3 years ago
Easy Sample Ap graphing 50pts! (Easy points!!) (ASAP) (URGENT) (Please check my other questions)​ Please
snow_lady [41]

Answer:

a)  See attachment 1.

b)  t² and D

c)  See attachment 2.

d)  g = 9.8 m/s² (1 d.p.)

Step-by-step explanation:

<h3><u>Part (a)</u></h3>

See attachment 1.  The line of best fit is shown in red.

<h3><u>Part (b)</u></h3>

The quantities the student should graph in order to produce a <u>linear relationship</u> between the two quantities are t² and D.

<h3><u>Part (c)</u></h3>

Make a table of values of t² and D:

\begin{array}{|l|l|l|l|l|l|}\cline{1-6} \rm t^2& 0.0196& 0.1024& 0.2116 & 0.3481& 0.3969\\\cline{1-6} \rm D & 0.10 & 0.50& 1.00 & 1.70 & 2.00\\\cline{1-6}\end{array}

<u>Plot</u> a graph of D against t² and draw a line of best fit (see attachment 2).

<h3><u>Part (d)</u></h3>

From inspection of the graph, the line of best fit passes through the origin (0, 0) and (0.1024, 5.0).  Therefore, use these two points to find the slope of the line:

\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{0.5-0}{0.1024-0}=4.8828125...\:\rm m/s^2

Therefore:

\rm \implies \dfrac{1}{2}g=4.8828125...\:\rm m/s^2

\rm \implies g=2 \cdot 4.8828125...\:\rm m/s^2

\rm \implies g=9.8\:\rm m/s^2\:(1\:d.p.)

5 0
2 years ago
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