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Katena32 [7]
3 years ago
7

On a coordinate plane, the center of a circle P is at the point (2, 15) . Point M is located on the circle at (7, 3). Which equa

tion describes circle P?
Mathematics
1 answer:
katrin [286]3 years ago
8 0

Answer: (x - 2)^2 + (y - 15)^2 = 13^2

Step-by-step explanation:

We know that the general equation for a circle is:

(x - a)^2 + (y - b)^2 = R^2

Where:

(a, b) is the center of the circle

R is the radius of the circle.

First, we know that the center of the circle is the point P, (2, 15)

Now, we also know that point M, (7, 3), is located at the circle.

Then we know that the radius of the circle will be equal to the distance between point P and point M.

Remember that the distance between two points (a, b) and (c, d) is:

Distance = √( (a - c)^2 + (b - d)^2)

Then in our case, we have:

Distance = √( (2 - 7)^2 + (15 - 3)^2) = √(25 + 144) = 13

This means that the radius of the circle is R = 13.

Now we know the radius of the circle and the center of the circle, then we can write the equation of the circle as:

(x - 2)^2 + (y - 15)^2 = 13^2

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Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = <em><u>population proportion</u></em>.

So, Null Hypothesis, H_0 : p = 0.013      {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, H_A : p > 0.013      {means that this is an unusually high number of faulty modems}

The test statistics that would be used here <u>One-sample z-test</u> for proportions;

                             T.S. =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~  N(0,1)

where, \hat p = sample proportion faulty modems= \frac{10}{367} = 0.027

           n = sample of modems = 367

So, <u><em>the test statistics</em></u>  =  \frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }

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The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. <u>Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.</u>

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that this is an unusually high number of faulty modems.

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